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3 years ago

Calculate the solubility of silver oxalate, ag2c2o4, in pure water. ksp = 1.0 × 10-11

Chemistry

1 answer:

aksik [14]3 years ago

6 0

Answer is: the solubility of silver oxalate is a. 1.4 × 10-4 m.

Chemical reaction (dissociation) of silver oxalate in water:
Ag₂C₂O₄(s) → 2Ag⁺(aq) + C₂O₄²⁻(aq).
Ksp(Ag₂C₂O₄) = [Ag⁺]²·[C₂O₄²⁻].
[C₂O₄²⁻] = x; solubility of oxalate ion.

[Ag⁺] = 2[C₂O₄²⁻] = 2x
1.0·10⁻¹¹ = (2x)² · x = 4x³.

x = ∛1.0·10⁻¹¹ ÷ 4.

x = 1.4·10⁻⁴ M.

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Which college classes would a student most likely take to become an oceanographer? Select 4 choices.

Setler [38]

Answer:

marine biology

coastal ecology

astronomy

meteorology

Explanation:

As a college student, to study oceanography one will have to take classes in the field of marine biology, coastal ecology, astronomy and meteorology.

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Oceanography is a merger of geology, biology, chemistry, physics as it pertains to the ocean.

There is no need to study human anatomy to study oceanography.
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3 years ago

"To determine the amount of heroin in the mixture, you dissolve 1.00 g of the white powdery mixture in water in a 100.0-mL volum

UkoKoshka [18]

Explanation:

Formula to calculate osmotic pressure is as follows.

Osmotic pressure = concentration × gas constant × temperature( in K)

Temperature = $25^{o} C$

= (25 + 273) K

= 298.15 K

Osmotic pressure = 531 mm Hg or 0.698 atm (as 1 mm Hg = 0.00131)

Putting the given values into the above formula as follows.

0.698 = $C \times 0.082 \times 298.15 K
$

C = 0.0285

This also means that,

$\frac{\text{moles}}{\text{volume (in L)}}$ = 0.0285

So, moles = 0.0285 × volume (in L)

= 0.0285 × 0.100

= $2.85 \times 10^{-3
}$

Now, let us assume that mass of $C_{12}H_{23}O_{5}N$ = x grams

And, mass of $C_{12}H{22}O_{11}$ = (1.00 - x)

So, moles of $C_{12}H_{23}O_{5}N = \frac{mass}{\text{molar mass}}$

= $\frac{x}{369}$

Now, moles of $C_{12}H_{22}O_{11} = \frac{(1.00 - x)}{342}$

= $\frac{x}{369} + \frac{(1.00 - x)}{342}$

= $2.85 \times 10^{-3}$

= x = 0.346

Therefore, we can conclude that amount of $C_{12}H_{23}O_{5}N$ present is 0.346 g and amount of $C_{12}H_{22}O_{11}$ present is (1 - 0.346) g = 0.654 g.

4 0

3 years ago

What is the atmic number of an elemts that has six protons and eight nuetrons?

cestrela7 [59]

Atomic Number-6
Mass Number-14

5 0

3 years ago

Determine the electron-group arrangement, molecular shape, and ideal bond angle(s) for each of the following:

lubasha [3.4K]

Solution :

a). $SO_3$

This compound is known as sulfur trioxide.

The molecular shape of sulfur trioxide is trigonal planer.

And the bond angle is 120°.

b). $N_2O$

This compound is known as Nitrous oxide. Here, nitrogen is in the center. There is no lone pair around the nitrogen atom and it forms two sigma bonds with the other two atoms.

It is linear in shape.

The bond angle between them is 180°.

c). $CH_2Cl_{2}$

This compound is known as the Dichloromethane.

The molecular shape of the compound is tetrahedral.

The bond angles is 120°

6 0

3 years ago

Water quality tests show the presence of a single heavy metal in the drinking water pulled from a local river. Residents are suf

just olya [345]

Answer:

One metal causes a chronic effect, compared to the other

Explanation:

because the question only said ONE is the same, didn't they? so that would mean that not all the metals are the same for both towns

4 0

3 years ago