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Mashcka [7]
3 years ago
14

Calculate the solubility of silver oxalate, ag2c2o4, in pure water. ksp = 1.0 × 10-11

Chemistry
1 answer:
aksik [14]3 years ago
6 0
Answer is: the solubility of silver oxalate is <span>a. 1.4 × 10-4 m.
</span>

<span>Chemical reaction (dissociation) of silver oxalate in water: 
Ag</span>₂C₂O₄(s) → 2Ag⁺(aq) + C₂O₄²⁻<span>(aq).
Ksp(Ag</span>₂C₂O₄) = [Ag⁺]²·[C₂O₄²⁻<span>].
[C</span>₂O₄²⁻] = x; solubility of oxalate ion.

[Ag⁺] = 2[C₂O₄²⁻<span>] = 2x
1.0·10</span>⁻¹¹ = (2x)² · x = 4x³.

x = ∛1.0·10⁻¹¹ ÷ 4.

x = 1.4·10⁻⁴ M.

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