Ask question

Ask question

All categories

Nimfa-mama [501]

3 years ago

13

Look at problem three if the price of a gallon of gas was $2.59 on Friday morning before the change in price what was the price

of a gallon of gas on Saturday

1 answer:

kaheart [24]3 years ago

5 0

Answer:

0.863

Step-by-step explanation:

You might be interested in

Can someone show me the work to this?

Oduvanchick [21]

To simplify the terms you execute a prime factorization (divide exactly by the smallest prime possible until you reach 1) which in the case of 320 would be: 320=2*2*2*2*2*2*5. Every factor which exists twice can be taken out of the root. Simplify the many 2s into 2 equal readable factors: 320=2*2*2*2*2*2*5=8*8*5

$\sqrt{320}=\sqrt{8*8*5}=8\sqrt{5}$

$\sqrt{162}=\sqrt{9*9*2}=9\sqrt{2}$

$\sqrt{108}=\sqrt{6*6*3}=6\sqrt{3}$

$\sqrt{125}=\sqrt{5*5*5}=5\sqrt{5}$

$\sqrt{63}=\sqrt{3*3*7}=3\sqrt{7}$

$\sqrt{432}=\sqrt{3*12*12}=12\sqrt{3}$

$\sqrt{112}=\sqrt{4*4*7}=4\sqrt{7}$

$\sqrt{98}=\sqrt{7*7*2}=7\sqrt{2}$

$\sqrt{12}=\sqrt{2*2*3}=2\sqrt{3}$

$\sqrt{726}=\sqrt{11*11*6}=11\sqrt{6}$

$\sqrt{300}=\sqrt{3*10*10}=10\sqrt{3}$

$\sqrt{8}=\sqrt{2*2*2}=2\sqrt{2}$

$\sqrt{27}=\sqrt{3*3*3}=3\sqrt{3}$

$\sqrt{18}=\sqrt{2*3*3}=3\sqrt{2}$

$\sqrt{196}=\sqrt{14*14}=14$

$\sqrt{30}=\sqrt{3*5*2}=\sqrt{3*10}$ and the end

5 0

3 years ago

Mariana [72]

Answer:

Option (D) is correct.

Step-by-step explanation:

In a triangle BCD , with b, c, d as the sides of triangle.

Sine rule states when we we divide side b by the sine of angle B then it is equal to side c divided by the sine of angle C and also equal to side d divided by the sine of angle D.

Using Sine rule,

$\frac{b}{\sin B}=\frac{c}{\sin C}=\frac{d}{\sin D}$

Consider the first and third ratio,

$\frac{b}{\sin B}=\frac{d}{\sin D}$

Substitute the values of d = 3 , b= 5 and ∠D=25°

$\Rightarrow \frac{5}{\sin B}=\frac{3}{\sin 25^{\circ}}$

$\Rightarrow \sin B=\frac{\sin 25^{\circ} \times 5}{3}}$

$\Rightarrow \sin B=45,135$

Thus, Measure of angle B is 45 and 135 as sinB is positive is first and 2nd quadrant.

Thus, option (D) is correct.

7 0

3 years ago

Read 2 more answers

Find x?<br> In 3x - In(x - 4) = ln(2x - 1) +ln3

earnstyle [38]

Answer:

$x = \displaystyle \frac{5 + \sqrt{17}}{2}$ .

Step-by-step explanation:

Because $3\, x$ is found in the input to a logarithm function in the original equation, it must be true that $3\, x > 0$ . Therefore, $x > 0$ .

Similarly, because $(x - 4)$ and $(2\, x - 1)$ are two other inputs to the logarithm function in the original equation, they should also be positive. Therefore, $x > 4$ .

Let $a$ and $b$ represent two positive numbers (that is: $a > 0$ and $b > 0$ .) The following are two properties of logarithm:

$\displaystyle \ln (a) + \ln(b) = \ln\left(a \cdot b\right)$ .

$\displaystyle \ln (a) - \ln(b) = \ln\left(\frac{a}{b}\right)$ .

Apply these two properties to rewrite the original equation.

Left-hand side of this equation:

$\begin{aligned}&\ln(3\, x) - \ln(x - 4)= \ln\left(\frac{3\, x}{x -4}\right)\end{aligned}$

Right-hand side of this equation:

$\ln(2\, x- 1) + \ln(3) = \ln\left(3 \left(2\, x - 1\right)\right)$ .

Equate these two expressions:

$\begin{aligned}\ln\left(\frac{3\, x}{x -4}\right) = \ln(3(2\, x - 1))\end{aligned}$ .

The natural logarithm function $\ln$ is one-to-one for all positive inputs. Therefore, for the equality $\begin{aligned}\ln\left(\frac{3\, x}{x -4}\right) = \ln(3(2\, x - 1))\end{aligned}$ to hold, the two inputs to the logarithm function have to be equal and positive. That is:

$\displaystyle \frac{3\ x}{x - 4} = 3\, (2\, x - 1)$ .

Simplify and solve this equation for $x$ :

$x^2 - 5\, x + 2 = 0$ .

There are two real (but not rational) solutions to this quadratic equation: $\displaystyle \frac{5 + \sqrt{17}}{2}$ and $\displaystyle \frac{5 - \sqrt{17}}{2}$ .

However, the second solution, $\displaystyle \frac{5 - \sqrt{17}}{2}$ , is not suitable. The reason is that if $x = \displaystyle \frac{5 - \sqrt{17}}{2}$ , then $(x - 4)$ , one of the inputs to the logarithm function in the original equation, would be smaller than zero. That is not acceptable because the inputs to logarithm functions should be greater than zero.

The only solution that satisfies the requirements would be $\displaystyle \frac{5 + \sqrt{17}}{2}$ .

Therefore, $x = \displaystyle \frac{5 + \sqrt{17}}{2}$ .

7 0

3 years ago

Matthew practiced playing the guitar for 2/3 hours. Natalie practiced playing the guitar 1 3/4 times as long as

belka [17]

Answer:

2/3*(7/4)=7/6 hours

Step-by-step explanation:

7 0

3 years ago

13. Solve the following:<br> a. 2.68 - 1.44 =<br> b. 5.05 X 0.04 =<br> c. 5.144 = 1.6 =

AURORKA [14]

A) 1.24 B) 0.202 and C) 3.215.

6 0

3 years ago

Read 2 more answers