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Nimfa-mama [501]
3 years ago
13

Look at problem three if the price of a gallon of gas was $2.59 on Friday morning before the change in price what was the price

of a gallon of gas on Saturday
Mathematics
1 answer:
kaheart [24]3 years ago
5 0

Answer:

0.863

Step-by-step explanation:


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The fish population of Lake Collins is decreasing at a rate of 3% per year. In 2004 there were about 1,300 fish. Write an expone
Sergeu [11.5K]
For this case we have a function of the form:
 y = A * (b) ^ x
 Where,
 A: initial amount
 b: decrease rate
 x: time in years
 Substituting values we have:
 y = 1300 * (0.97) ^ x

 For 2010 we have:
 y = 1300 * (0.97) ^ 6

y = 1083
 Answer:
 an exponential decay function to model this situation is:
 
y = 1300 * (0.97) ^ x
 The population in 2010 is:
 y = 1083
6 0
3 years ago
Read 2 more answers
Find the value of each variable
aniked [119]

Answer:

Answer d)

a= 10*\sqrt{3} b=5*\sqrt{3}, c=15, and d=5

Step-by-step explanation:

Notice that there are basically two right angle triangles to examine: a smaller one in size on the right and a larger one on the left, and both share side "b".

So we proceed to find the value of "b" by noticing that it the side "opposite side to angle 60 degrees" in the triangle of the right (the one with hypotenuse = 10). So we can use the sine function to find its value:

b=10*sin(60^o)= 10*\frac{\sqrt{3} }{2} = 5*\sqrt{3}

where we use the fact that the sine of 60 degrees can be written as: \frac{\sqrt{3} }{2}

We can also find the value of "d" in that same small triangle, using the cosine function of 60 degrees:

d=10*cos(60^o)=10* \frac{1}{2} = 5

In order to find the value of side "a", we use the right angle triangle on the left, noticing that "a" s the hypotenuse of that triangle, and our (now known) side "b" is the opposite to the 30 degree angle. We use here the definition of sine of an angle as the quotient between the opposite side and the hypotenuse:

sin(30^o)= \frac{b}{a} \\a=\frac{b}{sin(30)} \\a=\frac{5*\sqrt{3} }{\frac{1}{2} } \\a= 10*\sqrt{3}

where we used the value of the sine function of 30 degrees as one half: \frac{1}{2}

Finally, we can find the value of the fourth unknown: "c", by using the cos of 30 degrees and the now known value of the hypotenuse in that left triangle:

c=10*\sqrt{3} * cos(30^o)=10*\sqrt{3} *\frac{\sqrt{3} }{2} \\c= 5*3=15

Therefore, our answer agrees with the values shown in option d)

6 0
3 years ago
Marissa says that lines a and d will eventually
dexar [7]

Answer:The last one :)

Step-by-step explanation

8 0
3 years ago
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How do you solve for x in this type of equation?
lorasvet [3.4K]
I'm not too sure but i think:

A
_     r       =      x

Y
7 0
3 years ago
The "solutions" to a Quadratic Equation are where it is equal to zero. They are also
Cerrena [4.2K]

Answer:

One of them is the root

im not sure about the other one: I'd just call it the value of x

5 0
2 years ago
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