Question

Which reaction below represents the first ionization of sb?which reaction below represents the first ionization of ?sb2−(g) → sb3−(g) + e−sb+(g) + e− → sb2+(g)sb(g) + e− → sb−(g)sb−(g) + e− → sb2−(g)sb(g) → sb+(g) + e−?

Answer 1

Answer is: Sb(g) → Sb⁺(g) + e⁻.
Neutral atom in gas state lose one valence electron and become cation with postive charge.
The first ionisation energy is the energy required to remove one mole of the valence electrons from one mole of gaseous atoms to produce one mole of gaseous ions each with a charge of 1+.
Most metals have strong metallic bond, because strong electrostatic attractive force between valence electrons (metals usually have low ionization energy and lose electrons easy) and positively charged metal ions.

Answer 2

Answer: The reaction for the first ionization of Sb is $Sb(g)\rightarrow Sb^+(g)+e^-$

Explanation: Ionization of an atom is defined as the reaction when an electron is released from an isolated gaseous atom in their gaseous state.

General equation for the first ionization reaction is:

$X(g)\rightarrow X^+(g)+e^-$

So, from the given choices in the question, only one option represents the first ionization of Antimony atom (Sb-atom), which is $Sb(g)\rightarrow Sb^+(g)+e^-$