To calculate for the structure
of an element, you need to have a solid analyzer such as an x ray
diffractometer to determine the elements’ structure. It is hard to determine it
without any help of instrument because of its size.
Cobalt has an atomic number of 27, which means that its atoms have 27 protons in their nuclei. In a neutral cobalt atom, there is also 27 electrons. The ground state<span>electron </span>configuration<span> of cobalt is [Ar]3d74s2 .</span>
Answer:
The heat of combustion is -25 kJ/g = -2700 kJ/mol.
Explanation:
According to the Law of conservation of energy, the sum of the heat released by the combustion reaction and the heat absorbed by the bomb calorimeter is equal to zero.
Qcomb + Qcal = 0
Qcomb = - Qcal
The heat absorbed by the calorimeter can be calculated with the following expression.
Qcal = C × ΔT
where,
C is the heat capacity of the calorimeter
ΔT is the change in temperature
Then,
Qcomb = - Qcal
Qcomb = - C × ΔT
Qcomb = - 1.56 kJ/°C × 3.2°C = -5.0 kJ
Since this is the heat released when 0.1964 g o quinone burns, the energy of combustion per gram is:

The molar mass of quinone (C₆H₄O₂) is 108 g/mol. Then, the energy of combustion per mole is:

AppearanceClear, transparent and homogeneousCloudy, heterogeneous, at least two substances visibleParticle Sizemolecule in sizelarger than 10,000 AngstromsEffect of Light Tyndall Effectnone -- light passes through, particles do not reflect lightvariableEffect of Sedimentationnoneparticles will eventually settle ou
A compound that yields hydrogen ions when dissolved in a solution is an acid.
An example is an <em>aqueous solution of HCl.</em>