Question

Write the equations that represent the first and second ionization steps for hydroselenic acid (H2Se) in water. (Use H3O+ instead of H+.) First ionization step:

Answer 1

Answer:

The equations are

1) $H_{2}Se+H_{2}O--> H_{3}O^{+}+HSe^{-}$

2) $HSe^{-} +H_{2}O--> H_{3}O^{+}+Se^{-2}$

Explanation:

There are two ionization steps in the dissociation of hydroselenic acid.

In first dissociation the H₂Se loses one proton and forms hydrogen selenide ion as shown below:

$H_{2}Se+H_{2}O--> H_{3}O^{+}+HSe^{-}$

The next step is again removal of a proton from the base formed above.

$HSe^{-} +H_{2}O--> H_{3}O^{+}+Se^{-2}$