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Masja [62]
4 years ago
15

A chemist wants to calculate the amount of heat that is absorbed by a sample of copper as it is melted. Which constant should sh

e use?
Chemistry
2 answers:
Gnesinka [82]4 years ago
7 0

Answer:

Hfus

Explanation:

This is correct on edge.

Volgvan4 years ago
4 0
She needs to use the heat of fusion (ΔH(fusion)) and the equation q=mΔH(fusion) or q=nΔH(fusion)  depending on whether or not ΔH(fusion) is given in J/g or J/mol.  The reason why temperature is absent from the equation is that temperature does not change at a phase change, only the enthalpy does.

I hope his helps.  Let me know in the comments if anything is unclear.
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Substances made of two or more elements which are not chemically bonded are known as
11111nata11111 [884]
Substances that are not chemically bonded are mixtures.
8 0
3 years ago
Nitrous oxide (N2O) is used as an anesthetic (laughing gas) and in aerosol cans to produce whipped cream. It is also a potent gr
scZoUnD [109]

Answer:

five half lives

Explanation:

Half-life is the time required for a quantity to reduce to half of its initial value.

How many half lives it would take to reach 3.13% form 100% of it's initial concentration:

100% - 50% : First Half life

50% - 25%: Second Half life

25% - 12.5%: Third Half life

12.5% - 6.25%: Fourth Half life

6.25% - 3.125%: Fifth Half life

This means it would take five half lives to get to 3.125% (≈ 3.13%) of it's original concentration.

3 0
3 years ago
For the reaction: 2H2O2 --> 2H2 + 2O2, what is the total number of moles of O2 produced from the complete decomposition of 8
Softa [21]
2 H₂O₂ --> 2 H₂ + 2 O₂

2 moles H₂O₂ ------> 2 moles O₂
8 moles H₂O₂ ------> ?

moles O₂ = 8 x 2 / 2

moles O₂ = 16 / 2

= 8 moles

Answer C

hope this helps!
4 0
3 years ago
How many atoms of manganese are in 1.00 g?
andriy [413]

Answer:

\frac{1.00g}{54.9g. {mol}^{ - 1} }  =  0.0182\: mol\\  \\ 6.023 \times  {10}^{23}   \times 0.0182 \: mol  \\ = 0.109\times  {10}^{23} \: atoms

8 0
3 years ago
Read 2 more answers
Determine the theoretical yield of HCl if 60.0 g of BC13 and 37.5 g of H20 are reacted according to the following balanced react
Pie

Answer : The theoretical yield of HCl is, 56.1735 grams

Explanation : Given,

Mass of BCl_3 = 60 g

Mass of H_2O = 37.5 g

Molar mass of BCl_3 = 117 g/mole

Molar mass of H_2O = 18 g/mole

Molar mass of HCl = 36.5 g/mole

First we have to calculate the moles of BCl_3 and H_2O.

\text{Moles of }BCl_3=\frac{\text{Mass of }BCl_3}{\text{Molar mass of }BCl_3}=\frac{60g}{117g/mole}=0.513moles

\text{Moles of }H_2O=\frac{\text{Mass of }H_2O}{\text{Molar mass of }H_2O}=\frac{37.5g}{18g/mole}=2.083moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

BCl_3(g)+3H_2O(l)\rightarrow H_3BO_3(s)+3HCl(g)

From the balanced reaction we conclude that

As, 1 mole of BCl_3 react with 3 mole of H_2O

So, 0.513 moles of BCl_3 react with 3\times 0.513=1.539 moles of H_2O

From this we conclude that, H_2O is an excess reagent because the given moles are greater than the required moles and BCl_3 is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of HCl.

As, 1 mole of BCl_3 react to give 3 moles of HCl

So, 0.513 moles of BCl_3 react to give 3\times 0.513=1.539 moles of HCl

Now we have to calculate the mass of HCl.

\text{Mass of }HCl=\text{Moles of }HCl\times \text{Molar mass of }HCl

\text{Mass of }HCl=(1.539mole)\times (36.5g/mole)=56.1735g

Therefore, the theoretical yield of HCl is, 56.1735 grams

7 0
3 years ago
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