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4 years ago

9

The floor leader of the major party that holds fewer seats in a house of congress is called _____. 1.the speaker of the house 2.

the minority leader 3.the president of the senate 4.the party whip

2 answers:

Svetlanka [38]4 years ago

3 0

2.the minority leader

Sauron [17]4 years ago

3 0

THE ANSWER IS 2 THE MINORITY LEADER

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In a hydraulic lift, if the pressure exerted on the liquid by one piston is increased by 100 N/m2 , how much additional weight c

shepuryov [24]

Answer:

The additional weight and mass needed for lifting the other piston slowly is 2500 N and 254.92 kg, respectively.

Explanation:

By means of the Pascal's Principle, the hydraulic lift can be modelled by the following two equations:

Hydraulic Lift - Before change

$P = \frac{F}{A}$

Hydraulic Lift - After change

$P + \Delta P = \frac{F + \Delta F}{A}$

Where:

$P$ - Hydrostatic pressure, measured in pascals.

$\Delta P$ - Change in hydrostatic pressure, measured in pascals.

$A$ - Cross sectional area of the hydraulic lift, measured in square meters.

$F$ - Hydrostatic force, measured in newtons.

$\Delta F$ - Change in hydrostatic force, measured in newtons.

The additional weight is obtained after some algebraic handling and the replacing of all inputs:

$\frac{F}{A} + \Delta P = \frac{F}{A} + \frac{\Delta F}{A}$

$\Delta P = \frac{\Delta F}{A}$

$\Delta F = A\cdot \Delta P$

Given that $\Delta P = 100\,Pa$ and $A = 25\,m^{2}$ , the additional weight is:

$\Delta F = (25\,m^{2})\cdot (100\,Pa)$

$\Delta F = 2500\,N$

The additional mass needed for the additional weight is:

$\Delta m = \frac{\Delta F}{g}$

Where:

$\Delta F$ - Additional weight, measured in newtons.

$\Delta m$ - Additional mass, measured in kilograms.

$g$ - Gravitational constant, measured in meters per square second.

If $\Delta F = 2500\,N$ and $g = 9.807\,\frac{m}{s^{2}}$ , then:

$\Delta m = \frac{2500\,N}{9.807\,\frac{m}{s^{2}} }$

$\Delta m = 254.92\,kg$

The additional weight and mass needed for lifting the other piston slowly is 2500 N and 254.92 kg, respectively.

3 0

3 years ago

The equation E = MC squared relates energy and 1. Force 2. Gravity 3. Mass 4. Work

Ganezh [65]

The equation relates energy to mass

7 0

3 years ago

Read 2 more answers

If a motorbike of mass 150 kg moving with the speed of 36 km/hr produces

Aloiza [94]

Answer:

P = 7500 [W]

Explanation:

First We must use Newton's second law to find the force. Newton's Second Law tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

m = mass = 150 [kg]

a = acceleration = 5 [m/s²]

$F = 150*5\\F = 750 [N]$

We know that the work is determined by multiplying the force by the distance, in this way the units of the work are [N*m] which corresponds to 1 Joule [J].

And the power is determined by dividing the work by the time, in this way we have that [J/s] corresponds to 1 [W].

We must convert the speed from kilometers per hour to meters per second.

$36[km/hr]*1000[\frac{m}{1km}]*[\frac{1hr}{3600s} ]=10 [m/s]$

$P=F*v$

where:

P = power [W]

F = force = 750 [N]

v = 10 [m/s]

$P = 750*10\\P = 7500 [W]$

8 0

2 years ago

6. The temperature of a mass of tin increases from 24.0 degrees C to 34.0 degrees C when 250 J of thermal energy are added. Calc

irina [24]

Answer:

110 g

Explanation:

q = mCΔT

where q is heat, m is mass, C is specific heat capacity, and ΔT is change in temperature.

Given q = 250 J, C = 0.228 J/g/°C, and ΔT = 10.0 °C:

250 J = m (0.228 J/g/°C) (10.0 °C)

m = 110 g

6 0

3 years ago

He amount of current flowing in a circuit can be measured by

Papessa [141]

First question:
The magnitude of current flowing in a circuit is described in
units of Amperes. The device used to measure it is an Ampmeter,
or Ammeter.

Second question:
This question is so absurd that it should not be dignified with an
answer. Although 'E' is often used as the symbol for Electromotive
force, potential difference, and voltage, there's certainly no rule.
Anyone is free to use 'M', 'Q', 'Θ', or 'Щ' to denote voltage when
they write electrical formulas, just as long as they make sure to
explain the meaning of whatever symbols they use.

7 0

4 years ago