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Sveta_85 [38]
3 years ago
12

What potential difference is needed to stop an electron that has an initial velocity v=6.0

Physics
1 answer:
Assoli18 [71]3 years ago
7 0

Formula for kinetic energy of an object:

KE = 0.5mv²

m is the mass and v is the velocity.

Formula for the work done on a charged object by moving it through a potential difference:

W = ΔVq

ΔV is the potential difference and q is the charge of the object.

To find the potential difference needed to decelerate an electron to rest, set the work done on the electron equal to its kinetic energy:

W = KE

Substitute W = ΔVq and KE = 0.5mv²

ΔVq = 0.5mv²

Given values:

q = 1.6×10⁻¹⁹C

m = 9.11×10⁻³¹kg

v = 6.0m/s

Plug in the given values and solve for ΔV

ΔV×1.6×10⁻¹⁹ = 0.5×9.11×10⁻³¹×6.0²

ΔV = 1.02×10⁻¹⁰V

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2.55 m.

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3 0
3 years ago
Assume that the force exerted on each crutch by the ground is directed along the crutch, as the force vectors in the drawing ind
olya-2409 [2.1K]

Answer: 43 degrees

Explanation:

The force of the crutch can be broken into components.  The horizontal component of F is the static friction force keeping the crutch from sliding.  The vertical component is opposing the weight and is the Normal force.  Using the orientation of the angle q, we have the following

fs = Fx = F sin (angle (tita))

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Therefore,

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There for Angle tita Max = 43 degrees

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