A friend bought a bouquet of flowers. The bouquet had nine daisies and some roses. There were a total of 15 flowers in the bouqu
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Answer:
There is a 50% probability that the household has a dog, given that the household has a cat.
Step-by-step explanation:
We solve this problem building the Venn's diagram of these probabilities.
I am going to say that:
A is the probability that a household has a cat.
B is the probability that a household has a dog.
We have that:
In which a is the probability that a household has a cat but not a dog and is the probability that a household has both a cat and a dog.
By the same logic, we have that:
The probability that the household has a cat or a dog is 0.5
The probability that the household has a dog is 0.4
The probability that the household has a cat is 0.2.
So
What is the probability that the household has a dog, given that the household has a cat?
20% of the households have a cat, and 10% have both a cat and a dog. So
There is a 50% probability that the household has a dog, given that the household has a cat.
<u>Question Completion</u>
(b) Use the possibility diagram to calculate the probability that the product of the two numbers is
I) A prime number
ii) Not a perfect square
iii) A multiple of 5
iv) Less than or equal to 21
v) Divisible by 4 or 6
Answer:
I) 0.125 (ii)0.828125 (iii)0.234375 (iv) 0.625 (v)0.65625
Step-by-step explanation:
The sample space for an 8-sided fair die rolled twice is:
(a) The possibility diagram of the product of the two numbers appearing on the die in each throw
(b)
I) A prime number
Number of Products which are prime numbers = 8
ii) Not a perfect square
Number of products which are perfect squares =11
iii) A multiple of 5
Number of Products that are multiples of 5=15
iv) Less than or equal to 21
Number of products less than or equal to 21=40
v) Divisible by 4 or 6
Products Divisible by 4 or 6= 42