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Komok [63]
3 years ago
5

A sample of 65 observations is selected from one population with a population standard deviation of 0.75. The sample mean is 2.6

7. A sample of 50 observations is selected from a second population with a population standard deviation of 0.66. The sample mean is 2.59. Conduct the following test of hypothesis using the 0.08 significance level.
H0 : μ1 ≤ μ2
H1 : μ1 > μ2

a. Is this a one-tailed or a two-tailed test?
b. State the decision rule.
c. Compute the value of the test statistic.
d. What is your decision regarding H0?
e. What is the p-value?
Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
3 0

Answer:

Step-by-step explanation:

The null hypothesis is

H0 : μ1 ≤ μ2

The alternative hypothesis is

H1 : μ1 > μ2

a) it is a one-tailed and also a right tailed test

b) The decision rule is the basis on which the null hypothesis is rejected or not. If 0.08 > p value, reject H0. If 0.08 < p value, do not reject H0.

c) Since the population standard deviations are known, we would use the formula to determine the test statistic(z score)

z = (x1 - x2)/√σ1²/n1 + σ2²/n2

Where

x1 and x2 represents sample means

σ1 and σ2 represents population standard deviations

n1 and n2 represents number of samples

From the information given,

x1 = 2.67

x2 = 2.59

σ1 = 0.75

σ2 = 0.66

n1 = 65

n2 = 50

z = (2.67 - 2.59)/√0.75²/65 + 0.66²/50

= 0.08/√0.00865 + 0.008712

z = 0.61

From the normal distribution table, the probability value corresponding to the z score is 0.73

d) If 0.08 > 0.73, we would reject H0

e) the p-value is 0.73

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Answer:

i. 15.4

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Step-by-step explanation:

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8 0
2 years ago
In the figure below, O is between M and P, and N is the midpoint of MO. If =MP16 and =NO4, find OP.
Crazy boy [7]

Answer:

O is in between m and p so it is 6

Step-by-step explanation:

In the figure below, O is between M and P, and N is the midpoint of MO. If =MP16 and =NO4, find OP.

6 0
2 years ago
NEED HELP PLZ
Angelina_Jolie [31]

Answer:

0.14

Step-by-step explanation:

From the question given above, the following data were obtained:

Grade A = 5

Grade B = 10

Grade C = 15

Grade D = 3

Grade F = 2

Sample space (S) = 35

Probability of getting grade A, P(A) =?

The probability that a student obtained a grade of A can be obtained as follow:

Probability of getting grade A, P(A) =

Event of A (nA) / Sample space, (nS)

P(A) = nA/nS

P(A) = 5/35

P(A) = 0.14

Thus, probability that a student obtained a grade of A is 0.14

6 0
3 years ago
How do I show the relationship between the input and the output
alexgriva [62]

Answer:

Types of Relationships between the Input and Output

The scatter plot can be a useful tool in understanding the type of relationship that exist between the inputs (X’s) and the outputs (Y’s)

Step-by-step explanation:

1. No Relationship: The scatter plot can give an obvious suggestion if the inputs and outputs on the graph are not related. The points will be scattered throughout the graph with no particular pattern. For no relationship to exist, points have to be completely diffused. If some points are in concentration, then maybe a relationship does exist and our analysis has not been able to uncover it.

2. Linear and Non-Linear: A linear correlation exists when all the points are plotted close together. They form a distinct line. On the other hand points could be close together but they could form a relationship which has curves in it. The nature of the relationship has wide ranging implications.

3. Positive and Negative: A positive relationship between the inputs and the outputs is one wherein more of one input leads to more of an output. This is also known as a direct relationship.

On the other hand a negative relationship is one where more of one input leads to less of another output. This is also known as an inverse relationship.

4. Strong and Weak: The strength of the correlation is tested by how closely the data fits the shape. For instance if all the points are scattered very close together to form a very visible line then the relationship is strongly linear. On the other hand, if the relationship does not so obviously fit the shape then the relationship is weak.

I don't know if this was exactly what you were looking for; hope it is! :)

7 0
3 years ago
I don't get it at all could you go step by step with me
Elodia [21]
Okay, so if e=110, then so does c, because they are Alternate Interior angles. If c=110, then so does a, because they are Alternate Exterior. Angles a and b are on a straight line, which equals 180 altogether, and 180-110 is 70, so the measure of angle b is 70.

Hope this helps ya
3 0
3 years ago
Read 2 more answers
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