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Trava [24]
3 years ago
14

What is the least common multiple of 5 and 150

Mathematics
1 answer:
masha68 [24]3 years ago
5 0
Since 150 is a multiple of 5 and also a multiple of itself, the least common multiple of 5 and 150 is 150.
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Sally Jones pays $50.00 a month for group health insurance. There is a $300 deductible. Her medical bills for the last year were
neonofarm [45]

Given

Find out the  what was the insurance company's payment .  

To proof

As given

Sally Jones pays $50.00 a month for group health insurance

There is a $300 deductible

Her medical bills for the last year were $2,600.00

Linda's insurance company provided payment of 80% of the bills less the deductible.

Deductible

The  amount of money you will pay in an insurance claim before the insurance company starts paying you.

medical bill reducing the deductible = $2,600 -  $300

                                                             =  $2300

80 % is written in the decimal form

= \frac{80}{100}

= 0.8

than the equation becomes

Linda's insurance company provided payment  = 0.8× 2300

                                                                                = $1840

Therefore the the insurance company's payment be  $1840 .

Hence proved


   

5 0
4 years ago
in 2009 a total of R36 000 was invested in two accounts. One account earned 7% annual interest and the other earned 9% .The tota
Akimi4 [234]

a = amount invested at 7%

b = amount invested at 9%

we know the amount invested was ₹36000, thus we know that whatever "a" and "b" are, a + b = 36000.  We can also say that

\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{7\% of a}}{\left( \cfrac{7}{100} \right)a}\implies 0.07a~\hfill \stackrel{\textit{9\% of b}}{\left( \cfrac{7}{100} \right)b}\implies 0.09b

since we know the interest earned from the invested was ₹2920, then we say that 0.07a + 0.09b = 2920.

\begin{cases} a + b = 36000\\\\ 0.07a+0.09b=2920 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{using the 1st equation}}{a + b = 36000\implies \underline{b = 36000-a}}~\hfill \stackrel{\textit{substituting on the 2nd equation}}{0.07a~~ + ~~0.09(\underline{36000-a})~~ = ~~2920} \\\\\\ 0.07a+3240-0.09a=2920\implies 3240-0.02a=2920\implies -0.02a=-320 \\\\\\ a=\cfrac{-320}{-0.02}\implies \boxed{a=16000}~\hfill \boxed{\stackrel{36000~~ - ~~16000}{20000=b}}

5 0
2 years ago
Is 9.9 x 10/-28 in scientific notation
Katen [24]
Yes and no you do not use the slash you use ^
4 0
3 years ago
How many years are there in one bimillennium
olchik [2.2K]
A bi-millennium means two (bi) times thousand of years (millenium), this means that a bi millennium has 2000 years in it: two thousand years. 

The origin of this word is latin: because of this it also has the plural of "bimillennia"   <span />
5 0
4 years ago
@bobross plz help I have another question
enot [183]

Answer:

Average velocity is 32 miles/hr.

Step-by-step explanation:

Given that a particle moves on a line away from its initial position so that after t hours it is  s=6t^2+2t miles from its initial position.

We have to find the average velocity of the particle over the interval [1, 4].

As, average velocity is the change is position over the change in time.

s(4)=6(4)^2+2(4)=104

s(1)=6(1)^2+2(1)=8

∴ \text{Average Velocity=}\frac{s(4)-s(1)}{4-1}

                            =\frac{104-8}{3}=\frac{96}{3}=32miles/hr

Hence, average velocity is 32 miles/hr.

                                         

6 0
3 years ago
Read 2 more answers
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