Answer:
14175 j heat released.
Explanation:
Given data:
Mass of aluminium = 350.0 g
Initial temperature = 70.0°C
Final temperature = 25.0°C
Specific heat capacity of Aluminium = 0.9 j/g.°C
Heat changed = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Heat change:
ΔT = Final temperature - initial temperature
ΔT = 25.0°C - 70°C
ΔT = -45°C
Q = m.c. ΔT
Q = 350 g × 0.9 j/g.°C × -45°C
Q = -14175 j
I would probably say transformation of virus like molecules
Answer: The first step in balancing a chemical equation is to take inventory or count atoms on the reactant & the product side.
Explanation:
***If you found my answer helpful, please give me the brainliest. :) ***
Answer : The concentration of 
is, 0.12 M
Explanation :
Using Henry's law :
where,
= concentration of = ?
= partial pressure of = 4.5 atm
= Henry's law constant = 
Now put all the given values in the above formula, we get:
Thus, the concentration of is, 0.12 M
