All categories

3 years ago

Name two elements that have properties similar to those of beryllium and have average atomic masses higher than 130

Chemistry

1 answer:

sertanlavr [38]3 years ago

3 0

In the periodic table, elements of the same group are characterized by having the same similar properties.
So, first we will check the elements that lie within the same group as <span>beryllium and then we will attempt to choose the elements with atomic mass higher than 130.

So, elements in the same group as </span>beryllium are: magnesium, calcium, strontium, barium and radium.
Among these elements, we will find that:
radium has atomic mass of 226 amu
barium has atomic mass of 137.327 amu

Based on this, the two elements would be barium and radium.

You might be interested in

How many grams are in 1 mole of Pb3(PO4)4?

kvasek [131]

Answer:

In 1 mol of Pb₃(PO₄)₄ occupies 1001.48 grams

Explanation:

This compound is the lead (IV) phosphate.

Grams that occupy 1 mole, means the molar mass of the compound

Pb = 207.2 .3 = 621.6 g/m

P = 30.97 .4 = 123.88 g/m

O = (16 . 4) . 4 = 256 g/m

621.6 g/m + 123.88 g/m + 256 g/m = 1001.48 g/m

6 0

3 years ago

Read 2 more answers

A student plans a two-step synthesis of 1-ethyl-3-nitrobenzene from benzene. The first step is nitration of benzene to give nitr

arlik [135]

Answer:

Nitrobenzene is too deactivated (by the nitro group) to undergo a Friedel-Crafts alkylation.

Explanation:

The benzene ring in itself does not easily undergo electrophilic substitution reaction. Some groups activate or deactivate the benzene ring towards electrophilic substitution reactions.

-NO2 ia a highly deactivating substituent therefore, Friedel-Crafts alkylation of nitrobenzene does not take place under any conditions.

This reaction scheme is therefore flawed because Nitrobenzene is too deactivated (by the nitro group) to undergo a Friedel-Crafts alkylation.

7 0

3 years ago

A sealed container holding 0.0255 L of an ideal gas at 0.979 atm and 67 ∘ C is placed into a refrigerator and cooled to 41 ∘ C w

Aliun [14]

Answer:

$0.904 atm$

Explanation:

Using Gay Lusaac's law where there is no change in Volume. The pressure changes directly proportional to absolute T°

P₁/T₁ = P₂/T₂

P₁T₂/T₁

P₂ = $\frac{0.979 atm * 314k }{340k}$

P₂ = $0.904 atm$

5 0

3 years ago

Imagine that you could increase the gravitational

Monica [59]

Answer:

You weight would be doubled because gravitational force is doubled

2. Challenges:

a. Everyone’s body would have to adjust to the new weight and learn to walk again

b. Earth would be closer to the sun, so everything would be hotter on Earth

c. Flying airplanes and driving cars might no longer work at all (talk about how difficult this would make traveling)

3. Benefits:

a. Time would go by much slower so technically everyone would live longer

b. Balloons wouldn’t fly off anymore

4. You have to decide for yourself if you’d like it better or worse

Explanation:

5 0

3 years ago

Write the atomic symbols for isotopes with the following characteristics?

RideAnS [48]

<span>The isotopes are represented with two numbers before the atom symbol. One number means the atomic number (number of protons) and is placed on the left lower corner, the other number is that mass number (number of protons and neutrons) and is placed on the right upper corner. With that, 1) (8, 18) O: 8 is the atomic number and 18 is the mass number; 2) (10, 22) Ne: 10 is the atomic number and 22 is the mass number; 3) (25, 53) Mn: 25 is the atomic number and 53 is the mas number; 4) (11, 24) Na: 11 is the atomic number and 24 is the mass number; (22, 47) Ti: 22 is the atomic number and 47 is the mass number. The two numbers are placed without parentheses, again atomic number on the left lower corner and the mass number on the left upper corner.</span>

7 0

3 years ago