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ICE Princess25 [194]
4 years ago
15

Why do all the elements in Group 16 share similar properties?

Chemistry
1 answer:
geniusboy [140]4 years ago
5 0
D. They all have the same number of valence electrons.
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A piece of copper (12.0 g) is heated to 100.0 °C. A piece of chromium (also 12.0 g) is chilled in an ice bath to 0 °C. The speci
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Answer:

(a) Slightly greater than 20.0 °C

(b) T_F=293.46K=20.3^oC

Explanation:

Hello,

In this case, since we are talking about the equilibrium temperature that will be reached when the copper, chromium and water samples get in contact, the following equation is useful to describe such situation:

\Delta H_{water}+\Delta H_{copper}+\Delta H_{chromium}=0\\

Thus, in terms of masses, heat capacities and temperatures we consider the final temperature as the unknown:

m_{water}Cp_{water}(T_F-T_{water})+m_{copper}Cp_{copper}(T_F-T_{copper})+m_{chromium}Cp_{chromium}(T_F-T_{chromium})=0In such a way, by knowing that the heat capacities of copper and chromium are 0.386 and 0.45 J/(g°C) respectively, by solving for the equilibrium temperature one has:

T_F=\frac{m_{water}Cp_{water}T_{water}+m_{Cu}Cp_{Cu}T_{Cu}+m_{Cr}Cp_{Cr}T_{Cr}}{m_{water}Cp_{water}+m_{Cu}Cp_{Cu}+m_{Cr}Cp_{Cr}}

T_F=\frac{200.0g*4.184\frac{J}{g*K}* 293.15K+12.0g*0.386\frac{J}{g*K} *373.15K+12.0g*0.45\frac{J}{g*K}*273.15K}{200.0g*4.184\frac{J}{g*K}+12.0g*0.386\frac{J}{g*K} +12.0g*0.45\frac{J}{g*K}}\\\\T_F=293.46K=20.3^oC

Hence, the resulting temperature of water turns out slightly greater than 20.0 °C.

Best regards.

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