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snow_tiger [21]
3 years ago
13

An arctic weather balloon is filled with 4.96 L of helium gas inside a prep shed. The temperature inside the shed is 6. °C. The

balloon is then taken outside, where the temperature is 2. °C. Calculate the new volume of the balloon.
Chemistry
1 answer:
Virty [35]3 years ago
3 0

The new volume of the balloon : V₂ = 4.89 L

<h3>Further explanation</h3>

Given

V₁ = 4.96 L

T₁ = 6 + 273 = 279 K

T₂ = 2 + 273 = 275 K

Required

The new volume

Solution

Charles's Law  

When the gas pressure is kept constant, the gas volume is proportional to the temperature  

\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

Input the value :

V₂=V₁.T₂/T₁

V₂ = 4.96 x 275 / 279

V₂ = 4.89 L

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Read 2 more answers
Lead thiocyanate, Pb(SCN)2, has a Ksp value of 2.00×10−5.a) Calculate the molar solubility of lead thiocyanate in pure water. Th
kkurt [141]

Answer:

a) 1.71 × 10⁻³ M

b) 8.00 × 10⁻⁵ M

Explanation:

In order to calculate the solubility (S) of Pb(SCN)₂ we will use an ICE chart. We identify 3 stages (Initial, Change, Equilibrium) and complete each row with the concentration or change in the concentration.

       Pb(SCN)₂(s) ⇄ Pb²⁺(aq) + 2 SCN⁻(aq)

I                                 0                   0

C                               +S               +2S

E                                 S                  2S

The solubility product (Ksp) is:

Ksp = 2.00 × 10⁻⁵ = [Pb²⁺].[SCN⁻]² = S . (2S)² = 4S³

S = 1.71 × 10⁻³ M

<em>b) Calculate the molar solubility of lead thiocyanate in 0.500 M KSCN.</em>

KSCN is a strong electrolyte that dissociates to give 0.500 M K⁺ and 0.500M SCN⁻.

       Pb(SCN)₂(s) ⇄ Pb²⁺(aq) + 2 SCN⁻(aq)

I                                 0                 0.500

C                               +S                +2S

E                                 S                0.500 + 2S

Ksp = 2.00 × 10⁻⁵ = [Pb²⁺].[SCN⁻]² = S . (0.500 + 2S)²

In the term (0.500 + 2S)², 2S is negligible.

Ksp = 2.00 × 10⁻⁵ = S . (0.500)²

S = 8.00 × 10⁻⁵ M

4 0
3 years ago
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