Answer:
Explanation:
<em>First calculate how many moles of O2 you have. O is 16g/mole, so O2 is 32g/mole. 50/32 = 1.5625 moles. 1 mole of any gas at stp is 22.4 liters.</em>
<em>1.5625 × 22.4 = 35 liters.</em>
<em>Its been 15 years since I graduated HS, and I still remember how to do this. Do your own homework next time and in 15 years you may be able to do the same.</em>
<em>PLEASE</em><em> </em><em>THANK</em><em>,</em><em> </em><em>RATE</em><em> </em><em>AND</em><em> </em><em>FOLLOW</em><em> </em><em>ME</em><em> </em>
<em>AND</em><em> </em><em>PLEASE</em><em> </em><em>MARK</em><em> </em><em>ME</em><em> </em><em>AS</em><em> </em><em>"</em><em>BRAINLIEST</em><em>"</em><em> </em><em>ANSWER</em><em> </em>
<em>HOPE</em><em> </em><em>IT</em><em> </em><em>HELPS</em><em> </em><em>YOU</em>
I believe the answer would be through the movement of the molecules, the higher the temperature the more the molecules move around and vibrate.
Answer: 36.6°C
Explanation:
Given that,
initial pressure of helium (P1) = 1.20 atm
Initial temperature (T1) = 22.0°C
Final temperature (T2) = ?
Final pressure of helium (P2) = 2.00 atm
Since pressure and temperature are given while volume is constant, apply the formula for pressure's law
P1/T1= P2/T2
1.20 atm / 22.0°C = 2.00 atm / T2
Cross multiply
1.20 atm•T2= 2.00 atm•22°C
1.20 atm•T2= 44 atm•°C
Divide both sides by 1.20 atm
1.20 atm•T2/1.20 atm = 44 atm•°C/1.20 atm
T2 = 36.6°C
The lighter components are able to rise higher in the column before they are cooled to their condensing temperature, allowing them to be removed at slightly higher levels.
I hope this helps
Because if an electron was in an atom, it would allow two atoms to combine without exploding and disentigrating, therfore there would be no suck thing as nuclear fission (nuclear bomb)