<span>Balancing the choices, we have as follows:
A. 3AgBr + GaPO4 → Ag3PO4 +GaBr3
B. 3H2SO4 + 2B(OH)3 → B2(SO4)3 + 6H2O
C. Fe + 2AgNO3 → Fe(NO3)2 + 2Ag
D. C2H4O2 +2O2 → 2CO2 + 2H2O
Therefore, the correct answers are option A and B. Hope this answers the question. Have a nice day.</span>
Answer:
A) 3.17 g of Zn
Explanation:
Let's consider the reduction of Zn(II) that occurs in an electrolysis bath.
Zn⁺²(aq) + 2e⁻ → Zn(s)
We can establish the following relations:
- 1 min = 60 s
- 1 A = 1 C/s
- The charge of 1 mole of electrons is 96,468 C (Faraday's constant).
- When 2 moles of electrons circulate, 1 mole of Zn is deposited.
- The molar mass of Zn is 65.38 g/mol
The mass of Zn deposited under these conditions is:
Answer:
Hydrogen and Oxygen
Explanation:
also it can be written as H2O
if 105 grams burns completely
therefore
105 ×22.4/48=49
Answer:
The amount of ammonia needed is 33.3 g
Therefore, we can also say 1.96 moles of NH₃
Explanation:
The reaction is: 3CuO(s) + 2NH₃(g) → 3H₂O(l) + 3Cu(s) + N₂(g)
If we see stoichiometry, 3 moles of water can be produced by 2 moles of NH₃. We propose this rule of three:
3 moles of water can be produced by 2 mole of ammonia
Then, 2.94 moles of water, must be produced by (2.94 . 2) /3 =1.96 moles of NH₃
If we convert the moles to mass. 1.96 mol . 17 g /1mol = 33.3 g
