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4 years ago

Which is the correct name for P205?

Chemistry

1 answer:

shtirl [24]4 years ago

8 0

Answer:

Diphosphorus Pentaoxide

Explanation:

We have 2 atoms of Phosphorus and 5 atoms of Oxygen. It is a covalent bond.

2 is Di

5 is penta

Diphosphorus Pentaoxide

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What is the molarity of a solution with 2 moles of HCl in 2000 mL?

ikadub [295]

Answer:

"1 M" will be the right solution.

Explanation:

The given values are:

Number of moles,

= 2 moles

Volume of solution,

= 2000 mL

or,

= 2 L

Now,

The molarity of the solution will be:

= $\frac{Moles}{Liters}$

On substituting the values, we get

= $\frac{2}{2}$

= $1 \ M$

7 0

3 years ago

Which of the statements accurately describes compounds?

kow [346]

Answer:

True statements are 2, 4, 5

Explanation:

They can be broken down by chemical means because we need to break chemical bonds between two (or more) atoms.

They are pure substance because one can't separate them by physical means.

When one separate compounds on two (or more) substances, there are two (or more) different species and they all act differently.

7 0

3 years ago

Several interesting observations from the world around you are listed below. Which of these is NOT explained by a colligative pr

Phantasy [73]

Answer:

1.) At high altitude it takes longer to cook spaghetti.

Explanation:

The first even describes depression in boiling point due to reduction in external pressure . It is not a colligative property.

Depression of freezing point and elevation of boiling point due to impurity or addition of solute are colligative priperty.

5 0

4 years ago

Consider the following redox equation Mn(OH)2(s) + MnO4 –(aq)  MnO42 –(aq) (basic solution) When the equation is balanced with

inysia [295]

Answer : The balanced chemical equation is,

$2MnO_4^-(aq)+Mn(OH)_2(s)+4OH^-(aq)\rightarrow 3MnO_4^{2-}(aq)+2H_2O(l)$

The coefficient for $OH^-$ is, 4 and on reactant side of the equation $OH^-(aq)$ is present.

Explanation :

Rules for the balanced chemical equation in basic solution are :

First we have to write into the two half-reactions.
Now balance the main atoms in the reaction.
Now balance the hydrogen and oxygen atoms on both the sides of the reaction.
If the oxygen atoms are not balanced on both the sides then adding water molecules at that side where the more number of oxygen are present.
If the hydrogen atoms are not balanced on both the sides then adding hydroxide ion $(OH^-)$ at that side where the less number of hydrogen are present.
Now balance the charge.