Correct answer is magnesium bromide. This is an ionic compound with metal forming a positive ion - K+ and halogen forming a negative ion - Br-. When group 7 element form ions they have a suffix -ide. Bromine is the element and when it forms a negative ion bromine is called bromide with the suffix.
Magnesium gives 2 electrons and bromine can take only 1 electron, therefore 2 bromine atoms are needed. Therefore magnesium forms ionic bonds with 2 bromine atoms.
The compound is called magnesium bromide
Answer:
To be stable an atom will gain, lose, or share electrons to complete the outer most energy level (electron shell). Octet Rule because levels 2 and 3 need 8 electrons to be stable.
I have a feeling that #2 is the one.
Answer:
ΔH for the the reaction NO(g) + O(g) ⇒ NO₂(g) is ΔH= -304.1 kJ
Explanation:
<u>The complete question is:</u>
Consider the chemical equations shown here.
NO(g) + O₃(g) ⇒ NO₂(g) + O₂(g) (ΔH= -198.9 kJ
)
1.5 O₂(g) ⇒ O₃(g) (ΔH= 142.3 kJ
)
O(g) ⇒ 0.5 O₂(g) (ΔH= -247.5 kJ)
What is ΔH for the reaction shown below?
NO(g) + O(g) ⇒ NO₂(g)
Solution:
We have to use the Hess's Law: if a series of reagents react to give a series of products, the heat of reaction released or absorbed is independent of whether the reaction is carried out in one, two or more stages. That means enthalpy changes are additive.
NO(g)+ O₃(g) ⇒ NO₂(g) + O₂(g) (ΔH₁= -198.9 kJ
)
+
1.5 O₂(g) ⇒ O₃(g) (ΔH₂= 142.3 kJ
)
+
O(g) ⇒ 0.5 O₂(g) (ΔH₃= -247.5 kJ)
=
NO(g) + O₃(g) + 1.5 O₂(g) + O(g) ⇒ NO₂(g) + O₂(g) + O₃(g) + 0.5 O₂(g)
We remove the compounds that are in both members of the reaction:
NO(g) + O(g) ⇒ NO₂(g)
We only have to add the reactions so we add the value of each enthalpy change.
ΔH for the the reaction is given by:
ΔH= ΔH₁ + ΔH₂ + ΔH₃= -198.9 kJ +142.3 kJ -247.5 kJ= -304.1 kJ