Answer:
a) M HCl = 32.162 mol/L
b) m HCl = 15.873 mol/Kg
Explanation:
- wt% = (mass HCl / mass sln)×100
- δ HCl = mass HCl / Volume sln
- molarity = mol HCl / V sln (L)
- molality = mol HCl / Kg solvent
∴ MW HCl = 36.46 g/mol
assuming mass sln = 1 g
∴ mass sln = 1 g = g solvent + g solute
∴ solute: HCl
⇒ 0.37 = g HCl / g sln
⇒ g HCl = 0.37 g
⇒ g ste = 1 - 0.37 = 0.63 g
⇒ Kg ste = (0.63 g)×(Kg/1000 g) = 6.3 E-4 Kg
⇒ mol HCl = (0.37 g HCl)×(mol/36.46 g HCl) = 0.010 mol HCl
∴ V sln = (0.37 g)/(1.19 g/mL) = 0.3109 mL
⇒ V sln = (0.31 mL)×( L/1000 mL) = 3.109 E-4 L
a) molarity (M):
⇒ M HCl = 0.010 mol HCl / 3.109 E-4 L
⇒ M HCl = 32.162 mol/L
b) molality (m):
⇒ m HCl = ( 0.010 mol HCl) / (6.3 E-4 Kg)
⇒ m HCl = 15.873 mol/Kg
Answer:
Tin and Copper
Explanation:
The two atoms that could potentially form alloys are the tin and copper atoms.
Alloys are mixtures formed between two or more metals.
The goal of forming alloys is to take properties of one metal and add to that of another metal so as to enhance both materials.
Alloys are only formed between metals.
The only metal pair given from the choices is that of tin and copper.
Therefore, the two atoms that could potentially form alloys is tin and copper.
↪ Hello miss "galaxyu035" here's your answer for the question you wrote.
Answer :
No, <u>we cannot</u> stir silver nitrate solution with a copper spoon <u>because</u> , copper is more reactive than silver. Thus,it would displace silver from the silver nitrate solution forming copper nitrate.
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The balanced equation
for the reaction is:
6 HNCO(l) →
C3N3(NH2)3(l) + 3 CO2(g)
Convert amount of urea
from kg to moles
Molar Mass of urea = 60.06
g/mol so, 113 kg urea contains
113 kg / 60.06 = 1.88
mol urea
From balanced equation 6
moles of urea yields only 1 melamine, so divide the moles of urea by 6.
1.88 / 6 = 0.313 kmol
melamine
Now multiply 0.313 with
molar mass of melamine that is 126 g/mol
126 x 0.313 = 39.438 kg
Yield of overall
reaction is 73% so multiply 39.438 with 0.73
<span>39.438 x 0.73 = 28.799
kg is the answer</span>
