Call n, the first of those consecutive terms, then three consecutive terms are:n, n +1, and n +2.
So, the equation will be n + (n +1) + (n +2) = 467
=> n + n + 1 + n + 2 = 467
=> 3n + 3 = 467
All of them are valid forms of the equation for the sum of three consecutive integers is 467.
You can solve it now, if you want:
3n = 467 - 3
3n = 464
n = 464 / 3
n = 154.6
The solution means that there are not three consecutive numbers whose sume is 467.
You can verifiy that if you take 154 + 155 + 156 = 465
And 155 + 156 + 157 = 468
Assuming that C is the hypotenuse...
The formula you want to use is:
a^2 + b^2 = c^2
We start by squaring 10, which is 100. 5^2 is 25. Now that we have the values, we can do the equation.
100+25=c^2 100+25=
Now, square root
C= 11.180
Answer: a = 36 and b = 9
Explanation:
(6x-3)(6x+3)
= 36x² - 18x - 18x - 9
= 36x² - 9
(6x-3)(6x+3) = ax² - b
36x² - 9 = ax² - b
a = 36 and b = 9
Hope it helps!
<span>CD's must be 40 or below, so CD's total≤ 40
If you already have 27, than 27+(number of CDs bought)</span><span>≤ 40
27+x=40(max)
x=(40-27)
x=13 CDs can be bought, at maximum
so (CDs purchased)</span><span> ≤ 13
Therefore, 15 CDs would be too many to fit in the rack </span>
