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2 years ago

9

How many moles of each element are in one mole of Be(OH)2?

2 answers:

REY [17]2 years ago

8 0

B. 1 mole of beryllium, 2 moles of oxygen, 2 moles of hydrogen

Papessa [141]2 years ago

4 0

How many moles of each element are in one mole of Be(OH)2?

1 mole of beryllium, 1 mole of oxygen, 2 moles of hydrogen

1 mole of beryllium, 2 moles of oxygen, 2 moles of hydrogen CORRECT ANSWER

2 moles of beryllium, 2 moles of oxygen, 2 moles of hydrogen

2 moles of beryllium, 1 mole of oxygen, 1 moles of hydrogen

I took the test and B) was correct

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Which of the following conditions will result in a reaction that is spontaneous only at high temperatures?

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2 years ago

52.1 mL of aqueous 0.255 M Pb(NO3)2 is mixed with 38.5 mL of 0.415 M NaCl. The equation for the precipitate reaction is: Pb(NO3)

Elan Coil [88]

Answer:

0.0585 M

Explanation:

Pb(NO₃)₂ (aq) + 2NaCl (aq) → PbCl₂ (s) + 2NaNO₃ (aq)

First we <u>calculate the inital number of moles of each reagent</u>, using the <em>given volumes and concentrations</em>:

0.255 M Pb(NO₃)₂ * 52.1 mL = 13.3 mmol Pb(NO₃)₂

0.415 M NaCl * 38.5 mL = 16.0 mmol NaCl

Then we <u>calculate how many Pb(NO₃)₂ moles reacted with 16.0 mmoles of NaCl</u>, using the <em>stoichiometric coefficients of the reaction</em>:

16.0 mmol NaCl * $\frac{1mmolPb(NO_3)_2}{2mmolNaCl}$ = 8.00 mmol Pb(NO₃)₂

Now we <u>calculate the remaining number of Pb(NO₃)₂ moles after the reaction</u>:

13.3 mmol - 8.00 mmol = 5.30 mmol Pb(NO₃)₂

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5.30 mmol / (52.1 mL + 38.5 mL) = 0.0585 M

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