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Rasek [7]
3 years ago
7

4. What helps syrup and honey flow more easily out of a measuring cup?*

Chemistry
1 answer:
mixas84 [53]3 years ago
7 0
You can use grease or oil
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According to the website of the National Aeronautics and Space Administration (NASA), the average temperature of the universe is
charle [14.2K]

Answer : The temperature in degree Celsius is, -270.45^oC

Explanation :

The conversion used for the temperature from Kelvin to degree Celsius is:

^oC=K-273.15

where,

K = temperature in Kelvin

^oC = temperature in centigrade

As we are given the temperature in Kelvin is, 2.7

Now we have to determine the temperature in Kelvin.

^oC=K-273.15

^oC=2.7-273.15

^oC=-270.45

Therefore, the temperature in degree Celsius is, -270.45^oC

3 0
3 years ago
Question 17
Maurinko [17]
I will say this is True….?
7 0
2 years ago
Read 2 more answers
PLEASEEE HELP ITS DUE SOON!
erastovalidia [21]

Answer:

The correct answer would be C) Support

4 0
3 years ago
A chemistry student weighs out of sulfurous acid , a diprotic acid, into a volumetric flask and dilutes to the mark with distill
nadezda [96]

The question is incomplete, here is the complete question:

A chemistry student weighs out 0.104 g of sulfurous acid, a diprotic acid, into a 250.0 mL volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.0700 M NaOH solution. Calculate the volume of NaOH solution the student will need to add to reach the final equivalence point. Be sure your answer has the correct number of significant digits.

<u>Answer:</u> The volume of NaOH needed is 36.2 mL

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Given mass of sulfurous acid = 0.104 g

Molar mass of sulfurous acid = 82 g/mol

Volume of solution = 250 mL

Putting values in above equation, we get:

\text{Molarity of sulfurous acid}=\frac{0.104\times 1000}{82\times 250}\\\\\text{Molarity of sulfurous acid}=5.07\times 10^{-3}M

To calculate the volume of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_3

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=5.07\times 10^{-3}M\\V_1=250mL\\n_2=1\\M_2=0.0700M\\V_2=?mL

Putting values in above equation, we get:

2\times 5.07\times 10^{-3}\times 250.0=1\times 0.0700\times V_2\\\\V_2=\frac{2\times 5.07\times 10^{-3}\times 250}{1\times 0.0700}=36.2mL

Hence, the volume of NaOH needed is 36.2 mL

5 0
3 years ago
63 C = _____ 63 K 336 K 210 K 163 K
swat32
T K = ºC + 273

T = 63 + 273

T = 336 K

hope this helps!

4 0
3 years ago
Read 2 more answers
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