The amount of sodium bromide that would be formed from the reaction will be 7.5524 grams
<h3>Stoichiometric calculation</h3>
Looking at the equation of the reaction:
The mole ratio of CuBr2 and NaCl is 1:2.
Mole of 16.4 grams of CuBr2 = 16.4/223.37
= 0.0734 moles
Mole of 22.7 grams of NaCl = 22.7/58.44
= 0.3884 moles
Equivalent mole of NaCl = 0.1468 moles
Thus, NaCl is in excess while CuBr2 is limiting.
Mole ratio of CuBr2 and NaBr = 1:1
Mass of 0.0734 mole NaBr = 0.0734 x 102.894
= 7.5524 grams
More on stoichiometric calculation can be found here: brainly.com/question/8062886
Answer:
The final pressure is approximately 0.78 atm
Explanation:
The original temperature of the gas, T₁ = 263.0 K
The final temperature of the gas, T₂ = 298.0 K
The original volume of the gas, V₁ = 24.0 liters
The final volume of the gas, V₂ = 35.0 liters
The original pressure of the gas, P₁ = 1.00 atm
Let P₂ represent the final pressure, we get;
∴ The final pressure P₂ ≈ 0.78 atm.
I dont but maybe its c in my opinion
Radio waves, microwave, infrared, visible light, ultra violet, X-rays, gamma rays. that is lowest to highest and i no it is right mark as brainliest please
Answer:
0.42g/cm³ or 420kg/m³
Explanation:
1cm³ = 1ml
10 × 1cm³ = 10cm³
Density = Mass ÷ Volume
4.2g ÷ 10cm = 0.42 g/cm³
Density = 0.42g/cm³ or 420kg/m³
