A saturated solution can become supersaturated under which of the following conditions

Which best describes the difference between radiation and conduction? (1 point)

NNADVOKAT [17]

Answer:

B) Conduction requires two objects to be in physical contact.

Explanation:

Conduction is when two objects are directly touching each other. So, the objects must come in physical contact with each other.

6 0

3 years ago

What is produced by a neutralization reaction between an arrhenius acid and an arrhenius base?

stepladder [879]

Answer: Salt and Water

Explanation:

An Arrhenius acid (HCl) can best be defined as any substance that when added to water increases the concentration of H+ ions.

While an Arrhenius base (KOH) is any substance that when added to water increases the concentration of OH- ions.

When an Arrhenius acid such as HCl reacts with an Arrhenius base such as KOH, the end products will be salt and water, in a process called Neutralization Reaction.

HCl (aq) + KOH (aq) -------> KCl (aq) + H2O (l)

4 0

3 years ago

Given that Δ H ∘ f [ Br ( g ) ] = 111.9 kJ ⋅ mol − 1 Δ H ∘ f [ C ( g ) ] = 716.7 kJ ⋅ mol − 1 Δ H ∘ f [ CBr 4 ( g ) ] = 29.4 kJ

JulsSmile [24]

Answer:

283.725 kJ ⋅ mol − 1

Explanation:

C(s) + 2Br2(g) ⇒ CBr4(g) , Δ H ∘ = 29.4 kJ ⋅ mol − 1

$\frac{1}{2}$ Br2(g) ⇒ Br(g) , Δ H ∘ = 111.9 kJ ⋅ mol − 1

C(s) ⇒ C(g) , Δ H ∘ = 716.7 kJ ⋅ mol − 1

4*eqn(2) + eqn(3) ⇒ 2Br2(g) + C(s) ⇒ 4 Br(g) + C(g) , Δ H ∘ = 1164.3 kJ ⋅ mol − 1

eqn(1) - eqn(4) ⇒ 4 Br(g) + C(g) ⇒ CBr4(g) , Δ H ∘ = -1134.9 kJ ⋅ mol − 1

so,

average bond enthalpy is $\frac{1134.9}{4}$ = 283.725 kJ ⋅ mol − 1

4 0

3 years ago

You know that 8.9 moles of solute particles are dissolved in that liquid solution. If the molarity of the solution is 25 M, how

pychu [463]

Answer:

V = 0.356 L

Explanation:

In this case, we need to use the following expression:

M = n/V (1)

Where:

M: molarity of solution (mol/L or M)

n: moles of solute (moles)

V: Volume of solution (Liters)

From these expression, we can solve for V:

V = n/M (2)

Now, replacing the given data we can solve V:

V = 8.9 / 25

V = 0.356 L

5 0

3 years ago

If the reduction reaction has a reduction potential of 0.1 V, and the oxidation reaction has a reduction potential of -0.4V, and

aleksley [76]

Answer : The value of ΔG expressed in terms of F is, -1 F

Explanation :

First we have to calculate the standard electrode potential of the cell.

$E^o=E^o_{cathode}-E^o_{anode}$

or,

$E^o=E^o_{reduction}-E^o_{oxidation}$

$E^o=(0.1V)-(-0.4V)=+0.5V$

Now we have to calculate the standard cell potential.

Formula used :

$\Delta G^o=-nFE^o$

where,

$\Delta G^o$ = Gibbs free energy = ?

n = number of electrons = 2

F = Faraday constant

$E^o$ = standard e.m.f of cell = +0.5 V

Now put all the given values in this formula, we get the Gibbs free energy.

$\Delta G^o=-(2\times F\times 0.5)$

$\Delta G^o=-1F$

Therefore, the value of ΔG expressed in terms of F is, -1 F

5 0

3 years ago