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Vikki [24]
3 years ago
5

28. Rewrite the Scientific Notation into expanded form (normal number). 8.675309 x 10

Mathematics
1 answer:
Aleks [24]3 years ago
3 0
86.75309 is the answer
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The graph shows the temperature of ice cream in an ice chest during an overnight trip. What is the domain of this function?
mariarad [96]

Let

x-------> the number of hours

y------> the temperature in degrees Fahrenheit

we know that

For x=0\ hours

y=-10\°\ F

For x=30\ hours

y=30\°\ F

The domain of the function is the interval----------> [0,30]

0\ hours \leq x\leq 30\ hours

The range of the function is the interval----------> [-10,30]

-10\°\ F \leq y\leq 30\°\ F

therefore

<u>the answer is</u>

The domain is all real numbers 0 through 30

4 0
3 years ago
Read 2 more answers
182 – (4 + 92) answer thank you
Nikitich [7]

Answer:

86

Step-by-step explanation:

182 – (4 + 92)

I have big brain

5 0
2 years ago
Mary and Mike went to the store to buy colored pencils for their science class.mike bought a 12-pack for 1.69,and Mary bought a
sweet-ann [11.9K]

12-pack for 1.69 is a better buy

<em><u>Solution:</u></em>

Given that, Mike bought a 12-pack for 1.69 and Mary bought a 24-pack for 3.18

We have to find which is the better buy

First we have to find the unit rate

Unit rate is cost of 1 pack

<em><u>Mike bought a 12-pack for 1.69</u></em>

Therefore,

Cost of 12 pack = 1.69

Cost of 1 pack is found by dividing 1.69 by 12

cost\ of\ 1\ pack = \frac{1.69}{12} = 0.14083

Thus unit rate of Mike is 0.14083 dollar per pack

<em><u>Mary bought a 24-pack for 3.18</u></em>

Cost of 24 pack = 3.18

Cost of 1 pack is found by dividing 3.18 by 24

cost\ of\ 1\ pack = \frac{3.18}{24} = 0.1325

Thus unit rate of Mary is 0.1325 dollars

<em><u>On comparing both the unit rate</u></em>

0.14083>0.1325

Thus unit rate of Mike is larger

Thus, 12-pack for 1.69 is a better buy

3 0
2 years ago
El ancho de un rectángulo es 15 pies menos que
Karolina [17]

Answer:

II. Longitud, L = 70 metros.

I. Ancho = 55 metros.

Step-by-step explanation:

Deje que la longitud del rectángulo sea L.

Deje que el ancho del rectángulo sea W.

Dados los siguientes datos;

Perímetro del rectángulo = 250 m

Traduciendo el problema verbal a una expresión algebraica, tenemos;

W = L - 15

Matemáticamente, el perímetro de un rectángulo viene dado por la fórmula;

P = 2 (largo + ancho)

250 = 2 (L + L - 15)

250 = 2 (2L - 15)

250 = 4L - 30

4L = 250 + 30

4L = 280

L = 280/4

Longitud, L = 70 m

Para encontrar el ancho;

W = L - 15

W = 70 - 15

Ancho = 55 m

3 0
2 years ago
In triangle , side and the perpendicular bisector of meet in point , and bisects . If and , what is the area of triangle
stich3 [128]

In triangle ABC, side AC and the perpendicular bisector of BC meet in point D, and BD bisects ∠ABC。 If AD = 9 and DC = 7, 145–√5  is the area of a triangle.

I supposed here that [ABD] is the perimeter of ▲ ABD.

As  BD  is a bisector of  ∠ABC ,

ABBC=ADDC=97

Let  ∠B=2α

Then in isosceles  △DBC

∠C=α

BC=2∗DC∗cosα=14cosα

Thus  AB=18cosα

The Sum of angles in  △ABC  is  π  so

∠A=π−3α

Let's look at  AC=AD+DC=16 :

AC=BCcosC+ABcosA

16=14cos2α+18cosαcos(π−3α)

[1]8=7cos2α−9cosαcos(3α)

cos(3α)=cos(α+2α)=cosαcos(2α)−sinαsin(2α)=cosα(2cos2α−1)−2cosαsin2α=cosα(4cos2α−3)

With  [1]

8=cos2α(7−9(4cos2α−3))

18cos4−17cos2α+4=0

cos2α={12,49}

First root lead to  α=π4  and  ∠BDC=π−∠DBC−∠C=π−2α=π2 . In such case  ∠A=π−∠ABD−∠ADB=π4, and  △ABD  is isosceles with  AD=BD. As  △DBC  is also isosceles with  BD=DC=7,  AD=7≠9.

Thus first root  cos2α=12  cannot be chosen and we have to stick with the second root  cos2α=49. This gives  cosα=23  and  sinα=5√3.

The area of a triangle ABD=12h∗AD  where h  is the distance from  B  to  AC.

h=BCsinC=14cosαsinα

Area of  triangle ABD=145–√5

= 145–√5.

Incomplete question please read below for the proper question.

In triangle ABC, side AC and the perpendicular bisector of BC meet in point D, and BD bisects ∠ABC。 If AD = 9 and DC = 7, what is the area of triangle ABD?

Learn more about the Area of the triangle at

brainly.com/question/23945265

#SPJ4

6 0
2 years ago
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