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statuscvo [17]
3 years ago
5

A student states that an exothermic chemical reaction can transfer its heat only by convection and conduction. Which disproves t

his student's statement? Exothermic reactions often produce light.
Conduction cannot occur in a liquid.
Gases often rise from the surface of a reaction.
Convection currents form during chemical reactions.
Chemistry
2 answers:
Over [174]3 years ago
6 0
b is the right answer

denis-greek [22]3 years ago
3 0

Answer: Option (b) is the correct answer.

Explanation:

A chemical reaction in which there is release of heat is known as an exothermic reaction. And a reaction in which heat is absorbed by reactant molecules is known as an endothermic reaction.

In conduction, two objects of different temperature are placed adjacent to each other. As a result, heat flows from hotter object to colder object.

Conduction occurs in solid substances.

On the other hand, in convection, when two fluids (liquid or gas) are heated together then molecules of more dense (colder) fluid sink at the bottom. Whereas molecules of less dense (hotter) fluid rises at the top.

Hence, we can conclude that the student's statement conduction cannot occur in a liquid, is disproved.

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A sample of calcium phosphate was found to have a mass of 125.3 g. How many molecules were contained in the sample?
Viktor [21]

The answer for the following problem is mentioned below.

  • <u><em>Therefore number of molecules(N) present in the calcium phosphate sample are  19.3 × 10^23 molecules.</em></u>

Explanation:

Given:

mass of calcium phosphate (Ca_{3}(PO_{4} )_{2} ) = 125.3 grams

We know;

molar mass of calcium phosphate  (Ca_{3}(PO_{4} )_{2} ) = (40×3) + 3 (31 +(4×16))

molar mass of calcium phosphate  (Ca_{3}(PO_{4} )_{2} ) = 120 + 3(95)

molar mass of calcium phosphate  (Ca_{3}(PO_{4} )_{2} )  = 120 +285 = 405 grams

<em>We also know;</em>

No of molecules at STP conditions(N_{A}) = 6.023 × 10^23 molecules

To solve:

no of molecules present in the sample(N)

We know;

\frac{m}{M} =\frac{N} }{}N÷N_{A}

\frac{405}{125.3} =\frac{N}{6.023*10^23}

N =(405×6.023 × 10^23) ÷ 125.3

N = 19.3 × 10^23 molecules

<u><em>Therefore number of molecules(N) present in the calcium phosphate sample are  19.3 × 10^23 molecules</em></u>

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Answer:

<u><em>See attachment for explanations.</em></u>

Explanation:

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hope ths help and if you want more information go to this website: science.jrank.org

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