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statuscvo [17]
3 years ago
5

A student states that an exothermic chemical reaction can transfer its heat only by convection and conduction. Which disproves t

his student's statement? Exothermic reactions often produce light.
Conduction cannot occur in a liquid.
Gases often rise from the surface of a reaction.
Convection currents form during chemical reactions.
Chemistry
2 answers:
Over [174]3 years ago
6 0
b is the right answer

denis-greek [22]3 years ago
3 0

Answer: Option (b) is the correct answer.

Explanation:

A chemical reaction in which there is release of heat is known as an exothermic reaction. And a reaction in which heat is absorbed by reactant molecules is known as an endothermic reaction.

In conduction, two objects of different temperature are placed adjacent to each other. As a result, heat flows from hotter object to colder object.

Conduction occurs in solid substances.

On the other hand, in convection, when two fluids (liquid or gas) are heated together then molecules of more dense (colder) fluid sink at the bottom. Whereas molecules of less dense (hotter) fluid rises at the top.

Hence, we can conclude that the student's statement conduction cannot occur in a liquid, is disproved.

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Which element has 19 electrons surrounding the nuclei of its atoms?
QveST [7]
I think its potassium
5 0
3 years ago
Consider the following balanced equation:
algol [13]

Moles of PF₃ : 4

<h3>Further explanation</h3>

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

Reaction

\tt P_4(s)+6F_2(g)\rightarrow 4PF_3(g)

1.25 moles of P₄(s) is reacted with 6 moles of F₂(g)

Limiting reactant : the smallest ratio (mol divide by coefficient)

P₄ : F₂ =

\tt \dfrac{1.25}{1}\div \dfrac{6}{6}=1.25\div 1\rightarrow F_2~limiting~reactant(smallest~ratio)

mol PF₃ based on mol of limiting reactant(F₂), so mol PF₃ :

\tt \dfrac{4}{6}\times 6~moles=4~moles

8 0
3 years ago
Aqueous sulfuric acid reacts with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . If of sodium sulfa
notka56 [123]

Answer:

27%

Explanation:

Hello,

The following information is missing, but I found it: "1.92 g of sodium sulfate is produced from the reaction of 4.9 g of sulfuric acid and 7.8 g of sodium hydroxide" so the undergoing chemical reaction is:

2NaOH+H_2SO_4-->Na_2SO_4+2H_2O

Now, to compute the percent yield, we must first establish the limiting reagent to subsequently determine the theoretical yield of sodium sulfate because the real (1.92g) is already given, thus, we consider the following procedure:

n_{NaOH}=7.8gNaOH*\frac{1molNaOH}{40gNaOH}=0.2molNaOH\\n_{H_2SO_4}=4.9gH_2SO_4*\frac{1molH_2SO_4}{98gH_2SO_4}=0.050molH_2SO_4\\

- The moles of sodium hydroxide that completely react with 0.05 moles of sulfuric acid are:

0.2molNaOH*\frac{1molH_2SO_4}{2molNaOH}=0.098molH_2SO_4

As this number is higher than the previously computed 0.05 moles of available sulfuric acid, one states that the sulfuric acid is the limiting reagent. Now, the theoretical grams of sodium sulfate are found via:

0.05molH_2SO_4*\frac{1molNa_2SO_4}{1mol H_2SO_4} *\frac{142.04gNa_2SO_4}{1molNa_2SO_4} =7.1gNa_2SO_4

Finally, the percent yield turns out into:

Y=\frac{1.92g}{7.1g} *100

Y=27.0%

Best regards.

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