Question

The deepest trench in the world is 11,000 m in depth. Assuming sea water to have a constant density of 1050 kg/m, determine the pressure at this point in atmospheres.

Answer 1

Answer:

113406825 N/m²

Explanation:

The pressure at depth of 11,000 m can be calculated by:

Pressure = Atmospheric pressure + Pressure  due to height

Atmospheric pressure = 101325 N/m²

Also,  

$P_{height}=\rho\times g\times h$

Where,  

$\rho$ is the density of water ($\rho=1050\ kg/m^3$)

g is the gravitational acceleration = 9.81 m/s²

h = 11,000 m

$P_{height}=1050\ kg/m^3\times 9.81\ m/s^2\times 11000\ m$

Pressure  due to height = 113305500 N/m²

Pressure = Atmospheric pressure + Pressure  due to height = 101325 N/m² + 113305500 N/m² = 113406825 N/m²

Answer 2

Answer:

113406825 N/m²

Explanation:

The pressure at depth of 11,000 m can be calculated by:

Pressure = Atmospheric pressure + Pressure  due to height

Atmospheric pressure = 101325 N/m²

Also,  

Where,  

is the density of water ()

g is the gravitational acceleration = 9.81 m/s²

h = 11,000 m

Pressure  due to height = 113305500 N/m²

Pressure = Atmospheric pressure + Pressure  due to height = 101325 N/m² + 113305500 N/m² = 113406825 N/m²