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svp [43]
3 years ago
9

Which explains the change in ionization energy that occurs between removing the first and second electrons from an atom?

Chemistry
1 answer:
Novay_Z [31]3 years ago
4 0
The change that exist in ionization energy that occurs between removing the first and second electrons from an atom is that the <span> ionization energy increases because the ratio of the protons to electrons increases. The answer is letter B.</span>
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If you obtain 3.0 grams of aspirin from an experiment that could make no more than 3.14 grams, what is the percent yield?
Masteriza [31]

Answer:

96%

Explanation:

To find the percent yield, we can use this equation

\frac{Actual}{Theoretical} *100

The actual yield of aspirin is 3.0 and the theoretical is 3.14 in this case, so just plug the numbers in.

\frac{3.0}{3.14} *100\\\\ =96

Thus the percent yield is 96%

;)

3 0
3 years ago
List the substances Ar, Cl2, CH4, and CH3COOH, in order of increasing strength of intermolecular attractions. List the substance
Viefleur [7K]

Answer:

Order of increasing strength of intermolecular attraction:

CH_3COOH > Cl_2 > CH_4 > Ar

Explanation:

CH_3COOH can form hydrogen bond as H atom is attached with electronegative atom O.

Rest three, Cl_2,  CH_4,  Ar are non-polar molecules.

In non-polar molecules, van der Waal's intermolecular forces of attractions exist. Hydrogen bonding is stronger intermolecular attraction then van der Waal's intermolecular forces of attraction, hence, CH_3COOH has strongest intermolecular attractions.

Ar will have least intermolecular attraction, as it behaves almost as ideal gas and there is no intermolecular attraction exist between molecules of ideal gases.

Molecular size and mass of Cl_2 is high as compared to CH_4.

van der Waals intermolecular forces of attraction increases with increase in size.

Therefore,

Order of increasing strength of intermolecular attraction will be:

CH_3COOH > Cl_2 > CH_4 > Ar

8 0
3 years ago
Read 2 more answers
How many calories of heat are required to raise the temperature of 1.00kg of water from 10.2 degrees Celsius to 26.8 degrees Cel
Vika [28.1K]

Answer:

Explanation:

we know that specific heat is the amount of heat required to raise the  temperature of substance by one degree mathmeticaly

Q=mcΔT

ΔT=T2-T1

ΔT=26.8-10.2=16.6

C for water is 4.184

therefore

Q=1.00*4.184*16.6

Q=69.4 j

now we have to covert joule into calorie

1 calorie =4.2 j

x calorie=69.4 j/2

so 69.4 j =34.7 calorie thats why 34.7 calorie heat is required to raise the temperature of water from 10.2 to 26.8 degree celsius

6 0
3 years ago
Calculate the energy (in kJ) required to heat 10.1 g of liquid water from 55 oC to 100 oC and change it to steam at 100 oC. The
Maksim231197 [3]

Answer:

           \large\boxed{\large\boxed{24.6kJ}}

Explanation:

<u>1. Energy to heat the liquid water from 55ºC to 100ºC</u>

     Q=m\times C\times \Delta T

  • m = 10.1g
  • C = 4.18g/JºC
  • ΔT = 100ºC - 55ºC = 45ºC

     Q=10.1g\times 4.18J/g\ºC\times 45\ºC=1,899.81J

<u>2. Energy to change the liquid to steam at 100ºC</u>

      L=\lambda \times n

  • λ = 40.6kJ/mol
  • n = 10.1g / 18.015g/mol = 0.5606mol

      L=40.6kJ/mol\times 0.5604mol=22.76214kJ=22,762.14J

<u>3. Total energy</u>

       1,899.81J+22,762.14J=24,661.95J\approx24,662J\approx24.6kJ

7 0
3 years ago
What is the volume of a sample if the density is 2.35 g/mL and the mass is 33.67 g?
lawyer [7]
  • Density=2.35g/mL
  • Mass=33.67g

\\ \star\sf\longmapsto Density=\dfrac{Mass}{Volume}

\\ \star\sf\longmapsto Volume=\dfrac{Mass}{Density}

\\ \star\sf\longmapsto Volume=\dfrac{33.67}{2.35}

\\ \star\sf\longmapsto Volume=14.32mL

6 0
3 years ago
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