Given the reaction 2Pb(s)+O2(g)= 2PbO(s) and a reactant amount of 451.4 grams, we are asked for the yield of the reaction. The amount of lead present produces 451.4/207.2 *( 2/2) *(223.2) via 100% conversion, 486.26 grams lead (II) oxide. hence the percent yield is 356.7g /<span>486.26 g or equal to 73.35 percent</span>
Answer:

Explanation:
Given that:
Half life =
days
Where, k is rate constant
So,
The rate constant, k = 0.00007 days⁻¹
Using integrated rate law for first order kinetics as:
Where,
is the concentration at time t
is the initial concentration
Given:
5 % is lost which means that 0.05 of
is decomposed. So,
= 1 - 0.05 = 0.95
t = ?
t = 732.76 days = 
The correct answer is Reference Point
If Bc is the first horizontal line there, the solid is melting and going into the liquid state