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stiv31 [10]
3 years ago
6

At one time in the Earth’s history, many people thought the world was flat. Which best explains why the model of the Earth is no

w round?
Chemistry
1 answer:
GenaCL600 [577]3 years ago
5 0

Answer:

<u>Models are limited by science - the more that was discovered, the better the model could be made.</u>

Explanation:

Models in science are meant to represent things in science. Since science controls the reliability of a model, when science changes, so does the model. Otherwise the model would be pseudoscientific.

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What compound/element is this? <br><br> (Easy)
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Answer:

C₃H₆ propene

Explanation:

Find the chemical formula by adding all the carbon and then all the hydrogen together.

5 0
3 years ago
A certain chemical reaction releases 27.4 kJ/g of heat for each gram of reactant consumed. How can you calculate what mass of re
Fed [463]

A chemical reaction of exothermic kind releases energy in the form of heat and light.

We are given that reactant releases 27.4kJ/g for every gram of reactant consumed.

We are required to find number of grams of reactant that has been consumed

It is also given that 880J of energy is released

Hence, grams of reactants consumed is 880/27.4gm

Disclaimer:

It has been asked by the student to leave the question as mathematical expression.

For further reference:

brainly.com/question/15000187?referrer=searchResults

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4 0
1 year ago
If the molecular weight of a semiconductor is 27.9 grams/mole and the diamond lattice constant is 0.503 nm, what is the density
adelina 88 [10]

Explanation:

The given data is as follows.

      Mass = 27.9 g/mol

As we know that according to Avogadro's number there are 6.023 \times 10^{26} atom present in 1 mole. Therefore, weight of 1 atom will be as follows.

            1 atoms weight = \frac{38}{6.023 \times 10^{26}}    

In a diamond cubic cell, the number of atoms are 8. So, n = 8 for diamond cubic cell.

Therefore, total weight of atoms in a unit cell will be as follows.

            = \frac{8 \times 27.9 g/mol}{6.023 \times 10^{26}}

            = 37.06 \times 10^{-26}

Now, we will calculate the volume of a lattice with lattice constant 'a' (cubic diamond) as follows.

                   = a^{3}

                   = (0.503 \times 10^{-9})^{3}

                   = 0.127 \times 10^{-27} m^{3}

Formula to calculate density of diamond cell is as follows.

               Density = \frac{mass}{volume}

                             = \frac{37.06 \times 10^{-26}}{0.127 \times 10^{-27} m^{3}}

                            = 2918.1 g/m^{3}

or,                         = 0.0029 g/cc       (as 1 m^{3} = 10^{6} cm^{3})

Thus, we can conclude that density of given semiconductor in grams/cc is 0.0029 g/cc.

4 0
3 years ago
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