Answer:
ASA
Step-by-step explanation:
You can show the angles at either end of segment BC in triangles MBC and LCB are congruent, so you have two angles and the segment between. The appropriate theorem in such a case is ASA.
It is obviously C. most obviously
Answer:
The answer to your question is the first option
Step-by-step explanation:
Write the division
7x³ - 7x² + 6x +4 Result
x + 1 7x⁴ - 0x³ - 1x² + 10x + 15
-7x⁴ - 7x³
0 - 7x³ - 1x²
+ 7x³ +7x²
0 + 6x² + 10x
- 6x² - 6x
0 + 4x + 15
- 4x - 4
0 + 11 Remainder
Result = 7x³ - 7x² + 6x + 4 + 11 / x + 1
So, the shortest side is 13, the other two fellows are two consecutive values.... ok... let's say the other leg is "a", a consecutive value to that will be a+1, so the hypotenuse is "a + 1" then
check the picture below
and surely you'd know what "a" is
For this case, we have the following expression:

We simplify the expression:
If we add similar terms, taking into account that different signs are subtracted and the sign of the greater one is placed, we have that 
So, we have to:

Answer:
-3x + x + 5 = -2x + 5