Multiples of 3 plus 1 remainder are:
3n+1
Multiples of 4 plus 1 remainder are:
4n+1
Since these multiples must be the same number must be a multiple of 12 plus a remainder of one, which is:
12n+1
And the smallest such three digit number is:
12n+1>99 subtract 1 from both sides
12n>98 divide both sides by 12
n>8.17
Since n must be an integer, n=9
So then number is 12n+1
12(9)+1=109
P = 2(L) +2(W)
P = 2(4x+3) + 2(2x)
answer
B. 2(4x+3) + 2(2x)
There would be 9 birds left. 10-1=9
Starting from what I know (the difference between ribbons), I decided to go from the bottom and work my way up. I then noticed a pattern (each sum was three more of the previous one), and decided to keep my pattern of the three numbers but not have to do any major mental work and instead add three to the previous sum until I got to 38.