We can assume that all<span> gravitational potential energy is converted into
kinetic energy of the object.</span><span>
<span>Hence, </span>GPE = KE
Where GPE is gravitational Potential Energy (J)
and KE is Kinetic Energy (J)
GPE = mgh
<span>Where, m is the mass of the object (kg), g is acceleration due to gravity (9.8 m s</span></span>⁻<span>²) and h is the height to the<span> object from ground (m).</span></span><span>
m = 0.18 kg
g = 9.8 m s</span>⁻²<span>
h = 45 m
Hence,
GPE = 0.18 kg x 9.8 m s</span>⁻² x 45 m<span>
= 79.38 J
≈ 79 J
<span>Hence, </span>KE = GPE = 79 J
<span>Hence, the
answer is '79 joules'.</span></span>
First, find moles of oxygen gas: (3.01 x10^23 molec.)/(6.02 x10^23) =0.5mol O2
Second, multiply moles by the standard molar volume of a gas at STP:(0.5mol)(22.4L) = 11.2L O2
Answer:
Benzene: 37.5 Torr
Methylbenzene: 12.5 Torr
Explanation:
By Raoult's Law, each substance in a gas mixture contributes to the total pressure of the mixture proportionally to their respective mole fraction. So,
Ppartial = x*P°
Where x is the mole fraction (0.5 for each one because it's equimolar), and P° is the vapor pressure.
Benzene: Ppartial = 0.5 * 75 = 37.5 Torr
Methylbenzene: Ppartial = 0.5 * 25 = 12.5 Torr
