Answer:
m AgCl = 28.395 g
Explanation:
- AgNO3(aq) + NaCl(aq) → AgCl(s) + NaNO3(aq)
∴ [AgNO3] = 0.156 mol/L
∴ V = 1.27L
⇒ mol AgNO3 = 0.156 mol/L * 1.27 L = 0.19812 mol AgNO3
mass AgCL:
⇒ m AgCl = 0.19812 mol AgNO3 * mol AgCl/molAgNO3 * 143.32gAgCl/molAgCl
⇒ m AgCl = 28.395 g
I believe the correct answer from the choices listed above is option A. The topic that the teacher is talking about would be distillation of a mixture. Gasoline is processed by distillation. Hope this answers the question. Have a nice day.
Answer:
Hydrosulfuric acid will act as limiting reactant.
Explanation:
Given data:
Mass of iron(III) chloride = 3243.0 g
Mass of hydrosulfuric acid = 511.8 g
Limiting reactant = ?
Solution:
Chemical equation:
2FeCl₃ + 3H₂S → Fe₂S₃ + 6HCl
Number of moles of iron(III) chloride:
Number of moles = mass/molar mass
Number of moles = 3243.0 g/ 162.2 g/mol
Number of moles = 20 mol
Number of moles of hydrosulfuric acid:
Number of moles = mass/molar mass
Number of moles = 511.8 g/ 34.1 g/mol
Number of moles = 15 mol
Now we will compare the moles of both reactant with products
FeCl₃ : Fe₂S₃
2 : 1
20 : 1/2 ×20 = 10
FeCl₃ : HCl
2 : 6
20 : 6/2 ×20 = 60
H₂S : Fe₂S₃
3 : 1
15 : 1/3 ×15 = 5
H₂S : HCl
3 : 6
15 : 6/3 ×15 = 30
Hydrosulfuric acid producing less number of moles of product thus, it will act as limiting reactant.
I need more information, there are meant to be coefficients in front of one of those ..
but you’d put .2 over the coefficients, and if there is not one, you put an X. then you will cross multiply, and divide if you have 2x or something greater than X.
Answer: a) Por la estequiometría de la reacción, vemos que: 2. 4. 2. 4. 3. 2. 4. 98 g de H ... a) ¿Qué volumen de ácido sulfúrico concentrado de densidad 1'84 g/mL y 96 ... a) ¿Cuántos moles de átomos de carbono hay en 1'5 moles se sacarosa 12 ... b) El volumen de la misma que debe tomarse para preparar 1 L de disolución de.
