Answer
given,
flow rate = p = 660 kg/m³
outer radius = 2.8 cm
P₁ - P₂ = 1.20 k Pa
inlet radius = 1.40 cm
using continuity equation
A₁ v₁ = A₂ v₂
π r₁² v₁ = π r₁² v₂



Applying Bernoulli's equation





v₂ = 1.97 m/s
b) fluid flow rate
Q = A₂ V₂
Q = π (0.014)² x 1.97
Q = 1.21 x 10⁻³ m³/s
It’s more dense than air and less dense than liquid!
Answer:
Given force=10lb
L1=4in converting to feet
But 0.08333ft= 1 inch
Then 4 inch is 0.3332
6inch is 0.49998
But hookes law states
F=Kx where F is force,K is the force constant ,X
K=F/X=10/0.3333=30N/m
Integrating this
Integral of 30x with limit 0.333 to 0.5
F=30x^2/2=15x^2substing the limit
F=(15(0.5^2-0.33^2)=2.08ft-lb
Explanation: