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pentagon [3]
3 years ago
7

Is it possible for you to take a hike and have the distance you cover be equal to the magnitude of your displacement?

Physics
1 answer:
kow [346]3 years ago
3 0

Distance can be equal to displacement ... if the motion is all in a straight line ... but distance can never be greater than displacement.

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The plug has a diameter of 30 mm and fits within a rigid sleeve having an inner diameter of 32 mm. Both the plug and the sleeve
Katena32 [7]

Answer:

P=740 KPa

Δ=7.4 mm

Explanation:

Given that

Diameter of plunger,d=30 mm

Diameter of sleeve ,D=32 mm

Length .L=50 mm

E= 5 MPa

n=0.45

As we know that

Lateral strain

\varepsilon _t=\dfrac{D-d}{d}

\varepsilon _t=\dfrac{32-30}{30}

\varepsilon _t=0.0667

We know that

n=-\dfrac{\epsilon _t}{\varepsilon _{long}}

\varepsilon _{long}=-\dfrac{\epsilon _t}{n}

\varepsilon _{long}=-\dfrac{0.0667}{0.45}

\varepsilon _{long}=-0.148

So the axial pressure

P=E\times \varepsilon _{long}

P=5\times 0.148

P=740 KPa

The movement in the sleeve

\Delta =\varepsilon _{long}\times L

\Delta =0.148\times 50

Δ=7.4 mm

6 0
2 years ago
When a court has "___ ___" they can hear a case once a lower court has ruled on it.
notka56 [123]
Your answer is going to be Appellate jurisdiction.
3 0
3 years ago
What does a worm and wheel mechanism do to torque and speed​
sergejj [24]

Answer:Explanation:

Image result for what does a worm and wheel mechanism do to torque and speed​

Like other gear arrangements, a worm drive can reduce rotational speed or transmit higher torque. ... Each full 360 degree turn of a single start worm advances the gear by one tooth. For a multi start worm the gear reduction equals the number of teeth on the gear divided by the number of starts on the worm.

6 0
2 years ago
What two kinds of motion combine to produce projectile motion?
Vikki [24]

Horizontal and Vertical are the two motions that combine to produce projectile motion.

4 0
2 years ago
A 10,000-kg railroad car travels down the track at 30 m/s and hits a second stationary railroad car of 20,000 kg. The cars becom
Ivanshal [37]

Answer:

10 m/s

Explanation:

The problem can be solved by using the law of conservation of momentum: the initial momentum has to be equal to the final momentum, so we can write the following

p_i = p_f

m_1 u_1 + m_2 u_2 = (m_1 +m_2 )v

where

m_1 = 10,000 kg is the mass of the first car

u_1=30 m/s is the initial velocity of the first car

m_2 = 20,000 kg is the mass of the second car

u_2 = 0 is the initial velocity of the second car

v is the final velocity of the two combined cars after the collision

Re-arranging the equation and substituting the numbers, we find

v=\frac{m_1 u_1 +m_2 u_2}{m_1+m_2}=\frac{(10,000)(30)-0}{10,000+20,000}=10 m/s


6 0
3 years ago
Read 2 more answers
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