The sonar pulse takes t=4.2 s to reach the ocean bottom and then to travel back tothe ship. If we call d the depth of the ocean bottom, this means that the sonar pulse covered a distance equal to 2d in a time of 4.2 s.
The speed of the sonar pulse is the speed of sound in water at 25C, so looking at the table is v=1493 m/s. Using the relationship
![v= \frac{S}{t}](https://tex.z-dn.net/?f=v%3D%20%5Cfrac%7BS%7D%7Bt%7D%20)
between space and time for a uniform motion, and keeping in mind that the total distance covered by the pulse is 2d, we can write:
![v= \frac{2d}{t}](https://tex.z-dn.net/?f=v%3D%20%5Cfrac%7B2d%7D%7Bt%7D%20)
which becomes
![d= \frac{vt}{2}= \frac{(1493 m/s)(4.2 s)}{2}=3135 m](https://tex.z-dn.net/?f=d%3D%20%5Cfrac%7Bvt%7D%7B2%7D%3D%20%5Cfrac%7B%281493%20m%2Fs%29%284.2%20s%29%7D%7B2%7D%3D3135%20m%20%20)
so, the ocean bottom is 3135 m deep.
Answer:
![T=9.42Nm](https://tex.z-dn.net/?f=T%3D9.42Nm)
Explanation:
From the question we are told that:
Radius ![r= 0.5 m](https://tex.z-dn.net/?f=r%3D%200.5%20m)
Current ![I= 3.0 A](https://tex.z-dn.net/?f=I%3D%203.0%20A)
Normal vector ![n=\frac{(2i - j +2k)}{3}](https://tex.z-dn.net/?f=n%3D%5Cfrac%7B%282i%20-%20j%20%2B2k%29%7D%7B3%7D)
Magnetic field ![B= (2i-6j) T](https://tex.z-dn.net/?f=B%3D%20%282i-6j%29%20T)
Generally the equation for Area is mathematically given by
![A=\pi r^2](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E2)
![A=3.1415 *0.5^2](https://tex.z-dn.net/?f=A%3D3.1415%20%2A0.5%5E2)
![A=0.7853 m^2](https://tex.z-dn.net/?f=A%3D0.7853%20m%5E2)
Generally the equation for Torque is mathematically given by
![T=A(i'*B)](https://tex.z-dn.net/?f=T%3DA%28i%27%2AB%29)
Where
![i'*B= \begin{bmatrix}2&-1&2\\2&-6&0\end{bmatrix}](https://tex.z-dn.net/?f=i%27%2AB%3D%20%5Cbegin%7Bbmatrix%7D2%26-1%262%5C%5C2%26-6%260%5Cend%7Bbmatrix%7D)
![X\ component\ of\ i'*B= [(-1 * 0)-(2*-6)]](https://tex.z-dn.net/?f=X%5C%20component%5C%20of%5C%20i%27%2AB%3D%20%5B%28-1%20%2A%200%29-%282%2A-6%29%5D)
![X\ component\ of\ i'*B=12](https://tex.z-dn.net/?f=X%5C%20component%5C%20of%5C%20i%27%2AB%3D12)
Therefore
![T=0.7853*12](https://tex.z-dn.net/?f=T%3D0.7853%2A12)
![T=9.42Nm](https://tex.z-dn.net/?f=T%3D9.42Nm)
The result of
changing a physical sound wave into an analogous electrical signal using a
transducer (such as a microphone) is called analogue audio. In this system, the rapid electrical level is
directly proportional to the rapid air pressure taken by the transducer. The analogue
signal is then augmented and can be kept on an analogue medium such as tape or transformed
further into a succession of discrete mathematical numbers. The advantages of
using this device is that it yields a subtle sound and is pleasing to the ear
by pushing the signal level and overdriving it. But the disadvantages are
editing it would be tedious and prone to degradation.
1) It's B. Ultraviolet rays cause substances to fluoresce.
2) It's D. The lens enlarges the image.
3) It's actually more powerful so it's B. People usually buy products based on quality than portability.
4) CORRECT
5) CORRECT