1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ICE Princess25 [194]
3 years ago
5

The tip of a pinwheel is 0.24 m from the center. The pinwheel spins 5 times each second. What is the tangential speed of the tip

of the pinwheel? 0.30 m/s 1.2 m/s 1.5 m/s 7.5 m/s
Physics
2 answers:
hjlf3 years ago
4 0

Answer:

D on edge

Explanation:

Whitepunk [10]3 years ago
3 0
When a body is moving in circular path at a distance r from its center its velocity at any instant will be directed tangentially. This is what we call tangential velocity. It is calculated as follows:

Vt = r(ω)

where ω = 5 rev/s (2π rad / rev) =  31.42 rad / s

<span>Vt = 0.24(31.42) = 7.5 m/s</span>
You might be interested in
La superficie de unas botas suman 400 cm2 y la persona que las usa tiene 45 kg de masa, calcula la presión que ejerce sobre el p
liubo4ka [24]

Answer:

11025 N / m²

Explanation:

Los siguientes datos se obtuvieron de la pregunta:

Área (A) = 400 cm²

Masa (m) = 45 Kg

Aceleración por gravedad (g) = 9,8 m / s²

Presión (P) =?

A continuación, determinaremos la fuerza aplicada. Esto se puede obtener de la siguiente manera:

Masa (m) = 45 Kg

Aceleración por gravedad (g) = 9,8 m / s²

Fuerza (F) =.?

F = m × g

F = 45 × 9,8

F = 441 N

A continuación, convertiremos 400 cm² a m². Esto se puede obtener de la siguiente manera:

1 cm² = 0,0001 m²

Por lo tanto,

400 cm² = 400 cm² × 0,0001 m² / 1 cm²

400 cm² = 0,04 m²

Por tanto, 400 cm² equivalen a 0,04 m².

Finalmente, determinaremos la presión ejercida de la siguiente manera:

Área (A) = 0.04 m².

Fuerza (F) = 441 N

Presión (P) =?

P = F / A

P = 441 / 0,04

P = 11025 N / m²

Por tanto, la presión ejercida es 11025 M / m²

4 0
3 years ago
the car starts from rest at s=0 and increases its speed at at=4m/s^2. Determine the time when the magnitude of acceleration beco
dem82 [27]

Answer:

<em>Time =  5 seconds</em>

<em>Distance = 50 meters</em>

Explanation:

<u>Constantly Accelerated Motion</u>

When the velocity of a moving object changes at a constant rate, called acceleration, the velocity changes in same amounts in the same times. The question has a mistake when asking when the acceleration is 20 m/s. If the acceleration is constant, the only variable that can change to that value is the velocity. The equation to calculate the speed is

v_f=v_o+a.t

And the distance s is

\displaystyle s=v_o.t+\frac{gt^2}{2}

Given the object starts from rest, vo=0 and vf=20 m/s at a=4\ m/s^2. We compute t

\displaystyle t=\frac{v_f-v_o}{a}=\frac{20-0}{4}

\boxed{t=5\ sec}

Now we compute s

\displaystyle s=0+\frac{4\times 5^2}{2}

\boxed{s=50\ m}

5 0
3 years ago
Earl is using his hands to hold a metal pan 10 centimeters above a hot burner. How can this scenario be changed to demonstrate c
Olenka [21]

Answer: touch the pan to the burner

Explanation:

There are three modes of heat transfer:

conduction, convection and radiation.  

For conduction, the heat transfers from a hot object to a cold object when the two are in contact.

For convection there is bulk motion of fluid occurs which transfers the heat.

For heat transfer by radiation, medium is not required.

Thus, to demonstrate conduction between pan and burner, the pan must touch the burner.

8 0
3 years ago
Read 2 more answers
What collides and creates a movement of heat called conduction?
lutik1710 [3]
The answer of this is C!!!
6 0
3 years ago
Can you have zero displacement and nonzero average velocity? Zero displacement and nonzero velocity? Illustrate your answers on
Svetlanka [38]

a) Not possible

b) Yes, it's possible (see graph in attachment)

Explanation:

a)

The average velocity of a body is defined as the ratio between the displacement and the time elapsed:

v=\frac{\Delta x}{\Delta t}

where

\Delta x is the displacement

\Delta t is the time elapsed

In this problem, we want to have zero displacement and non-zero average velocity. From the equation above, we see that this is not possible. In fact, if the total displacement is zero,

\Delta x = 0

And therefore as a consequence,

v=0

which means that the average velocity is zero.

B)

Here we want to have zero displacement and non-zero velocity. In this case, it is possible: in fact, we are not talking  about average velocity, but we are talking about (instantaneous) velocity.

On a position-time graph, the instantaneous velocity is the slope of the graph. Look at the graph in attachment. We see that the position of the object first increases towards positive value, then it decreases (the object starts moving backward), then becomes negative, then it increases again until returning to the original position, x = 0.

In all of this, we notice that the total displacement of the object is zero:

\Delta x = 0

However, we notice that the instantaneous velocity of the object at the various instants is not zero, because the slope of the graph is not zero.

Learn more about average velocity:

brainly.com/question/8893949

brainly.com/question/5063905

#LearnwithBrainly

3 0
3 years ago
Other questions:
  • The discovery of Uranus________.
    7·2 answers
  • How are sound energy and light energy similar?
    8·2 answers
  • $3.49/ gallon and other is $1.25/L which container of milk is a better deal
    7·2 answers
  • A car travels at 12 m/s, how far does it travel in 15 seconds
    9·1 answer
  • Why are L waves not usually seen on a seisogram?
    5·1 answer
  • A current of 6.0 A runs through a circuit for 2.5 minutes.
    10·2 answers
  • The size of the electrical potential is measured in
    9·1 answer
  • I have some balls I’m a girl
    7·1 answer
  • In Hans Oersted’s experiment, why did a compass needle move when an electric current flowed through a nearby wire?
    5·2 answers
  • What is the speed of light in a vacuum?
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!