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skelet666 [1.2K]
3 years ago
10

A motor attached to a 120 V/60 Hz power line draws an 8.40 A current. Its average energy dissipation is 850 W. How much series c

apacitance needs to be added to increase the power factor to 1.0?
Physics
1 answer:
stepladder [879]3 years ago
3 0

Answer:ttgyuygu

Explanation:

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A car initially going 61 ft/sec brakes at a constant rate (constant negative acceleration), coming to a stop in 7 seconds.
Bond [772]

Answer:

See the attachment below for the graphics in part (a)

The initial velocity for this time interval is u = 61ft/sec and the final velocity is 0m/s because the car comes to a stop.

This a constant acceleration motion considering the given time interview over which the brakes are applied. So the equals for constant acceleration motion apply here.

Explanation:

The full solution can be found in the attachment below.

Thank you for reading. I hope this post is helpful to you.

4 0
3 years ago
After an earthquake, which type of seismic wave arrives last at a seismometer?
amm1812
I believe L waves arrive last at a seismometer.
hope this helps!
8 0
3 years ago
[A] Write an expression for the equivalent resistance of three resistors connected in parallel.[ no derivation needed]
anzhelika [568]

Answer:

1) R1 + ((R2 × R3)/(R2 + R3))

2) 0.5 A

3) 3.6 V

Explanation:

1) We can see that resistors R2 and R3 are in parallel.

Formula for sum of parallel resistors; 1/Rt = 1/R2 + 1/R3

Making Rt the subject gives;

Rt = (R2 × R3)/(R2 + R3)

Now, Resistor R1 is in series with this sum of R2 and R3. Thus;

Total resistance of circuit = R1 + ((R2 × R3)/(R2 + R3))

2) R_total = R1 + ((R2 × R3)/(R2 + R3))

We are given;

R1 = 7.2 Ω

R2 = 8 Ω

R3 = 12 Ω

R_total = 7.2 + ((8 × 12)/(8 + 12))

R_total = 7.2 + 4.8

R_total = 12 Ω

Formula for current is;

I = V/R

I = 6/12

I = 0.5 A

3) since current through the circuit is 0.5 and R1 is 7.2 Ω.

Thus, potential difference through R1 is;

V = IR = 0.5 × 7.2 = 3.6 V

4 0
2 years ago
A roulette wheel with a 1.0m radius reaches a maximum angular speed of 18 rad/s before it stops 35 revolutions ( 220 rad ) after
Alex17521 [72]
Max ang. speed(u) = 18 rad/s
final ang. speed(v) = 0
ang. displacement(s) = 220 rad

ang. acceleration = (v^2 - u^2)/2s = -18^2 / 2*220 = -0.7364 rad/s^2

v = u +at
0 = 18 - 0.7364t
t = 18/0.7364
t = 24.44 seconds
4 0
3 years ago
IF a car trip 400 km in four hours what is the rate of speed that a car is traveling?
Andreas93 [3]

Speed = Distance/ Time

Speed = 400 / 4

Speed = 100 km/hr.

100 km per hour.
8 0
3 years ago
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