Answer:
Part a)

Part B)
percentage increase is
%
Explanation:
Part a)
As we know that the beat frequency is

after increasing the tension the beat frequency is decreased and hence the tension in string B will increase
So we have


Part B)
percentage increase in the tension of the string will be given as


now we have

so we have


so we have

percentage increase is

Answer:
A cosmic year is 365.25 days, some times called a side real year and is just the time it takes for us to go round the sun once.
A light year is the distance light travels in a year. Now light travels at about 186,262 miles a Second! Which is not slow by any ones book.
An experiment was conducted just after Christmas a few years ago. Two girls were selected from the audience and went into two phone boxes a few feet apart. They could only hear each other via the phones. The phone call went to a ground station about 200 miles away, then up to a geostationary coms satellite, back to a ground station 1/3 of the way around the world, then repeated, with a third satellite before being sent from another ground station back to London and the other phone box. We the audience could hear both sides of the conversation from both boxes. And could hear the delay between sending and receiving. So even at the speed of light, there was about 1.5 seconds of delay. So because distances in space are so vast that saying a star is x millions of miles away causes problems, you run out of zero’s! So our nearest other star is about 4.5 light years away. Our sun (our nearest start) is about 8 light minuets away. Varies slightly as our orbit is not 100% cirular.
I HOPE THIS IS HELPFUL.
Answer: Sirius, the brightest star in the sky, is 2.6 parsecs (8.6 light-years) from Earth, giving it a parallax of 0.379 arcseconds. Another bright star, Regulus, has a parallax of 0.042 arcseconds. Then, the distance in parsecs will be,23.46.
Explanation: To find the answer, we have to know more about the relation between the distance in parsecs and the parallax.
<h3>What is the relation between the distance in parsecs and the parallax?</h3>
- Let's consider a star in the sky, is d parsec distance from the earth, and which has some parallax of P amount.
- Then, the equation connecting parallax and the distance in parsec can be written as,


<h3>How to solve the problem?</h3>

- Thus, we can find the distance in parsecs as,

Thus, we can conclude that, the distance in parsecs will be, 23.46.
Learn more about the relation connecting distance in parsecs and the parallax here: brainly.com/question/28044776
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Answer:
In a standing sound wave in a pipe, nodes are regions of mean atmosphere pressure and low displacement.