All categories

3 years ago

Normally, atoms are electrically neutral because there are__.

Physics

1 answer:

spayn [35]3 years ago

8 0

Answer:

Equal number of protons and electrons

Explanation:

This principle of proton and electron equality was used by J.J. Thompson in the discovery of proton. After he had discovered the electron. He discovered that since atoms are electrically neutral, that means there must be equal number of protons to balance out the electrons present in the atom.

You might be interested in

If measuring experimental results, what can you predict about the work output of a 1200 Watt hair dryer?

Elden [556K]

I am 90% sure it’s A

3 0

3 years ago

Read 2 more answers

A sound wave has a frequency of 192Hz and travels the length of a football field, 91.4m in 0.267s. What is the period?

Vinvika [58]

Answer:1/192 seconds

Explanation:

Period=1÷frequency

Period=1÷192

Period=1/192 seconds

6 0

3 years ago

Compressions and rarefactions are characteristic of

Korvikt [17]

Answer:

Of longitudinal waves

Explanation:

Depending on the direction of the oscillation, there are two types of waves:

- Transverse waves: in a transverse wave, the oscillations occur perpendicularly to the direction of propagation of the wave. Examples are electromagnetic waves.

- Longitudinal waves: in a longitudinal wave, the oscillations occur parallel to the direction of propagation of the wave. In such a wave, the oscillations are produced by alternating regions of higher density of particles, called compressions, and regions of lower density of particles, called rarefactions. Examples of longitudinal waves are sound waves.

6 0

3 years ago

If it requires 8.0 J of work to stretch a particular spring by 2.0 cm from its equilibrium length, how much more work will be re

jenyasd209 [6]

Answer:

The amount of work done required to stretch spring by additional 4 cm is 64 J.

Explanation:

The energy used for stretching spring is given by the relation :

$E = \frac{1}{2}kx^{2}$ .......(1)

Here k is spring constant and x is the displacement of spring from its equilibrium position.

For stretch spring by 2.0 cm or 0.02 m, we need 8.0 J of energy. Hence, substitute the suitable values in equation (1).

$8 = \frac{1}{2}\timesk\times k \times(0.02)^{2}$

k = 4 x 10⁴ N/m

Energy needed to stretch a spring by 6.0 cm can be determine by the equation (1).

Substitute 0.06 m for x and 4 x 10⁴ N/m for k in equation (1).

$E = \frac{1}{2}\times4\times10^{4}\times (0.06)^{2}$

E = 72 J

But we already have 8.0 J. So, the extra energy needed to stretch spring by additional 4 cm is :

E = ( 72 - 8 ) J = 64 J

7 0

3 years ago

If a wave has speed of 235 m/s with a wavelength of 3 m, what is the frequency of the wave?

maria [59]

I think it’s 25 but I don’t know

5 0

2 years ago