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Kruka [31]
2 years ago
6

Find the distance between the given points. R(O, O) and S(6, 8) Distance =

Mathematics
1 answer:
Fittoniya [83]2 years ago
8 0

Answer:

distance = 10

2/7 /(22) = 10

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2. Koil and Karry want to order the figures from greatest to least
Tom [10]

Given:

Figures A, B and C.

To find:

The order of the figures and volume of each figure.

Solution:

<u>Figure A:</u>

Length = 10, Width = 2 and Height = 2

Volume of A = length × width × height

                     = 10 × 2 × 2

Volume of A = 40 cubic units

<u>Figure B:</u>

Length = 3, Width = 3 and Height = 1

Volume of B = length × width × height

                     = 3 × 3 × 1

Volume of B = 9 cubic units

<u>Figure C:</u>

Length = 6, Width = 3 and Height = 3

Volume of C = length × width × height

                     = 6 × 3 × 3

Volume of C = 54 cubic units

Order from greatest to least:

54 < 40 < 9

C < A < B

Hence Kurry said the correct answer.

7 0
3 years ago
Find the<br> area of the figure.
EastWind [94]

Answer:

22 sq ft

Step-by-step explanation:

8 0
3 years ago
Find sin 2a and cot 2a:
geniusboy [140]

Answer:

sin(2\alpha )=2(\frac{5}{12})(\frac{12}{13})=\frac{10}{13}\\cot(2\alpha ) = \frac{16511}{18720}

Step-by-step explanation:

\text{if } cos(\alpha)=\frac{12}{13}\\\text{That must mean we have a triangle with base 12, and hypotenuse 13.}\\\text{Using Pythagoras, we can determine the base of the triangle must be 5.}\\a^2+b^2=c^2 \text{, where c is the hypotenuse and a, b are the two other sides.}\\c^2-b^2=a^2\\\sqrt{c^2-b^2}=a\\\sqrt{13^2-12^2}=\sqrt{169-144}=\sqrt{25}=5\\\text{Therefore, }sin(\alpha) = \frac{5}{12}\\sin(2\alpha)=2sin(\alpha )cos(\alpha)\\\text{(From double angle formulae identities)}\\

sin(2\alpha )=2(\frac{5}{12})(\frac{12}{13})=\frac{10}{13}\\cos(2\alpha )=cos^2(\alpha)-sin^2(\alpha)\\cos(2\alpha )=(\frac{12}{13})^2-(\frac{5}{12})^2=\frac{16511}{24336}\\cot(2\alpha)=\frac{cos(2\alpha)}{sin(2\alpha)}=\frac{\frac{16511}{24336}}{\frac{10}{13}}=\frac{16511}{18720}

8 0
3 years ago
What are the coordinates of the centroid of a triangle with vertices J(−4, 2) , K(2, 4) , and L(0, −2) ?
Kryger [21]
Given the coordinates of the three vertices of a triangle ABC, 
the centroid coordinates are (x1+x2+x3)/3, (y1+y2+y3)/3
<span>so (-4+2+0)/3=-2/3, ]2+4+(-2)]/3=4/3
so the coordinates are (-2/3, 4/3)</span>
3 0
3 years ago
Read 2 more answers
PLS HURRY RATING BRAINLIEST !!!!!
storchak [24]
The form f(x) = a(bx) equals a. The initial value of the function f(x) = a(bx) is always a. This is due to the fact that an is not reliant on x. As a result, if x changes, bx will change as well, but a will not.
6 0
3 years ago
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