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SOVA2 [1]
3 years ago
7

Jane is a crime scene investigator. She wants to reveal small particles with high contrast. So, she positions the forensic lamp

at a very low angle against the surface. Which technique is she using? A. fluorescence B. oblique lighting C. absorption D. spectroscopy E. stereoscopy
Physics
1 answer:
qwelly [4]3 years ago
6 0

Answer:

Pretty sure it's B. Oblique Lighting

Explanation:

A. is clearly wrong, C. is also clearly wrong, D and E both have nothing to do with lighting, Oblique Lighting is defined as "using a light source positioned at a low angle. Oblique lighting is usually used to show detail by creating shadows on the surface of the evidence." Hope this helps.

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When resistance force is increased on a lever which of the following happens to the effort force?
Sauron [17]
When resistance force on a lever increases, nothing happens automatically. 
But if you want to keep lifting the load, then YOU must increase the force of
your effort in order to make it happen.
8 0
3 years ago
Reggie accidentally left his books on top of his car before he left for class. The books stayed on top of his car while he was d
Volgvan

Answer: When Reggie's car turned eastward, his books continued moving northward, causing them to slide off the top of his car. :)

8 0
3 years ago
Hiii :( this is the second question and not making sense to me at all please help <3 it’s due soon
harkovskaia [24]

Answer:

Socratic app

Explanation:

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7 0
3 years ago
77. The first law of motion applies to
Mama L [17]
In the first law, an object will not change its motion unless a force acts on it. So I think the answer is A. Only objects that are moving.
8 0
3 years ago
A uniform thin spherical shell of mass M=2kg and radius R=0.23m is given an initial angular speed w=18.3rad/s when it is at the
Rashid [163]

Answer:

47.8rad/s

Explanation:

For energy to be conserved.

The potential energy sustain by the object would be equal to K.E

P.E = m× g× h = 2 × 9.81× 3.5= 68.67J

Now K.E = 1/2 × I × (w1^2 - w0^2)

I = 2/3 × M × R2

= 2/3 × 2 × (0.23)^2= 0.0705

Hence

W1 = final angular velocity

Wo = initial angular velocity

From P.E = K.E we have;

68.67J = 1/2 × 0.0705 × (w1^2 - w0^2)

(w1^2 - w0^2) = 1948.09

W1^2 = 1948.09 + (18.3^2)

W1^2=2282.98

W1 = √2282.98

=47.78rad/s

= 47.8rad/s to 1 decimal place.

7 0
3 years ago
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