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TiliK225 [7]
4 years ago
8

In act 3, who says the following lines to Bottom?

Physics
1 answer:
Arlecino [84]4 years ago
3 0
A. Titania says this verse.

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What's an example for investigate
ludmilkaskok [199]
Investigate means to search for something or look in to something
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3 years ago
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It is safer for a car driver to be wearing a seat belt, compared with not wearing a seat belt, if the car is involved in a colli
Korolek [52]

Explanation: It is because when a car is moving both the car and the driver is in inertia of motion. When a car is involved in collision it comes to a sudden stop and the car comes into inertia of rest whereas the person still in inertia of motion moves forward and might result in major injuries. But this can be prevented by wearing a seatbelt

Hope it helps :)

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3 years ago
A ladder is balanced against a wall without moving. What<br> must be true about this ladder?
Mandarinka [93]

Answer:a no net force

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6 0
3 years ago
Cannonball a is launched across level ground with speed v₀ at an angle of 45. Cannonball b is launched from the same location wi
postnew [5]

Answer:

Cannonball b spends more time in the air than cannonball a.

Explanation:

Starting with the definition of acceleration, we have that:

a=\frac{\Delta v}{\Delta t}\\\\\Delta t= \frac{\Delta v}{a}

Since both cannonballs will stop in their maximum height, their final velocity is zero. And since the acceleration in the y-axis is g, we have:

\Delta t= -\frac{v_{oy}}{g}

Now, this time interval is from the moment the cannonballs are launched to the moment of their maximum height, exactly the half of their time in the air. So their flying time t_f is (the minus sign is ignored since we are interested in the magnitudes only):

t_f=2\frac{v_{oy}}{g}

Then, we can see that the time the cannonballs spend in the air is proportional to the vertical component of the initial velocity. And we know that:

v_{oy}=v_o\sin\theta\\\\\implies t_f=2\frac{v_o\sin\theta}{g}

Finally, since \sin60\°=\frac{\sqrt{3} }{2} and \sin45\°=\frac{\sqrt{2} }{2}, we can conclude that:

t_{fa}=\sqrt{2}\frac{v_o }{g} \\\\t_{fb}=\sqrt{3}\frac{v_o }{g}\\\\\implies t_{fb}>t_{fa}

In words, the cannonball b spends more time in the air than cannonball a.

5 0
3 years ago
¿ qué es un motor de explosión?
ArbitrLikvidat [17]

Answer:

es un motor de combustión interna con encendido por chispa.

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