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TiliK225 [7]
3 years ago
8

In act 3, who says the following lines to Bottom?

Physics
1 answer:
Arlecino [84]3 years ago
3 0
A. Titania says this verse.

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A seamount is an isolated land mass rising from the ocean floor.<br> a. True<br> b. False
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The answer is A, True.
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What type of electromagnetic wave does a light bulb and a radio antenna release?
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When the speed of the bottle is 2 m/s, the KE is kg m2/s2. When the speed of the bottle is 3 m/s, the KE is kg m2/s2. When the s
d1i1m1o1n [39]

mass of the bottle in each case is M = 0.250 kg

now as per given speeds we can use the formula of kinetic energy to find it

1) when speed is 2 m/s

kinetic energy is given as

K = \frac{1}{2}mv^2

K = \frac{1}{2}(0.250)(2)^2 = 0.5 J

2) when speed is 3 m/s

kinetic energy is given as

K = \frac{1}{2}mv^2

K = \frac{1}{2}(0.250)(3)^2 = 1.125 J

3) when speed is 4 m/s

kinetic energy is given as

K = \frac{1}{2}mv^2

K = \frac{1}{2}(0.250)(4)^2 = 2 J

4) when speed is 5 m/s

kinetic energy is given as

K = \frac{1}{2}mv^2

K = \frac{1}{2}(0.250)(5)^2 = 3.125 J

5) when speed is 6 m/s

kinetic energy is given as

K = \frac{1}{2}mv^2

K = \frac{1}{2}(0.250)(6)^2 = 4.5 J

3 0
3 years ago
Read 2 more answers
Based on the diagram of the two electrical circuits, assuming the lightbulbs are all identical, which circuit will draw more pow
pochemuha
In series connection  in orde to find the total resistance we add all the resistance capacity but in parallel, we take the 1/R  and resistance = V  hence the series connection takes up more power,
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A block of mass m slides down a frictionless ramp to a loop-the-loop with radius R. The mass starts from initial height such tha
Vera_Pavlovna [14]

Answer:

\frac{v^{2} }{R}

Explanation:

R = radius of the loop

m = mass of the block

v = speed of the block at top of the loop at point A

a = magnitude of acceleration of block at A

At point A, the block moves in a circle and hence experience centripetal force. Due to this centripetal force, the centripetal acceleration of the block can be given as

a = \frac{v^{2} }{R}

6 0
3 years ago
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