A) 5000 m²
b) A(x) = x(200 -2x)
c) 0 < x < 100
Step-by-step explanation:
b) The remaining fence, after the two sides of length x are fenced, is 200-2x. That is the length of the side parallel to the building. The product of the lengths parallel and perpendicular to the building is the area of the playground:
A(x) = x(200 -2x)
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a) A(50) = 50(200 -2·50) = 50·100 = 5000 . . . . m²
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c) The equation makes no sense if either length (x or 200-2x) is negative, so a reasonable domain is (0, 100). For x=0 or x=100, the playground area is zero, so we're not concerned with those cases, either. Those endpoints could be included in the domain if you like.
For this case we have a direct variation of the form:
Where,
- <em>k: proportionality constant
</em>
We must find the value of k.
For this, we use the following data:
Therefore, replacing values we have:
Rewriting:
Clearing the value of k we have:
Therefore, the direct variation equation is given by:
Answer:
The quadratic variation equation for the relatonship is:
Answer:
about 704 in 2
Step-by-step explanation:
surface area-2Ab+Pb*h
=2(13*8)+49.6(10)
=704
