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Karo-lina-s [1.5K]
4 years ago
10

Juanita is watering her lawn using the water stored in her rainwater tank the water in the tank drops 1/3 inch every 10 minutes

she waters. If the tanks water level is 4 feet how many days can Juanita water if she waters for 15 minutes each day?
Mathematics
2 answers:
Ilya [14]4 years ago
8 0
<span>Juanita is watering her lawn using the water that is stored by rainwater.
=> the water in the tank drops 1/3 inch in every 10 minutes she waters.
=> The tanks water level is 4 feet.
Question : Number of days can Juanita waters is she waters 15 minutes per day.
=> 4 feet is the total amount of water = 1 ft = 12 inches
=> 48 inches in total
=> 1/3 inch is used every 10 minutes = 0.33 inches
=> she waters 15 minutes per day = 0.495 inches in every 15 minutes
Solution
=> 48 inches / 0.495 inches per day
=> 96.97
So Juanita can use all the water in water tank for approximately 97 days.</span>



Cloud [144]4 years ago
4 0
The person before me rounded a bit, and i personally do not like it. If there is 4 feet, that is 48 inches. If ten minutes is a third of an inch, then 30 minutes is one inch. So 15 minutes is half an inch. If you use the water for 15 minutes (or half an inch a day) then you have 96 days exactly.
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Marina86 [1]

Answer: correct.

Step-by-step explanation:

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I don't under stand what is wrong.
MAXImum [283]

Answer:

In the first step, there is an issue when distributing the -3 to the terms inside of the parentheses. When multiplying the -3 to the -5, you would get an answer of +15, not -15.

The full correct process is:

(4m + 9) - 3(2m - 5) = 4m + 9 - 6m + 15

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One positive number is 14 less than another positive number. If the reciprocal of the smaller number is added to five times the
Kipish [7]

Let's call the two numbers s and l.


Given these variables, we can say: s = l - 14, based on the first sentence in the problem.


Also, remember that the reciprocal of a number is simply 1 divided by the number. Thus, we can say that:

\dfrac{1}{s} + 5\Big( \dfrac{1}{l} \Big) = \dfrac{1}{4}


To solve, we can simply substitute l -14 in for s in the second equation and solve.

\dfrac{1}{l - 14} + \dfrac{5}{l} = \dfrac{1}{4}

  • Set up

\dfrac{l}{l(l - 14)} + \dfrac{5(l - 14)}{l(l - 14)} = \dfrac{1}{4}

  • Get terms on the left side to a common denominator for easier addition

\dfrac{l + 5l - 70}{l(l - 14)} = \dfrac{1}{4}

  • Simplify

4(6l - 70) = l(l - 14)

  • Cross multiplication (\frac{a}{b} = \frac{c}{d} \Rightarrow ad = bc)

24l - 280 = l^2 - 14l

  • Simplify

l^2 - 38l + 280 = 0

  • Subtract 24l - 280 from both sides of the equation

(l - 10)(l - 28) = 0

  • Factor left side of the equation

l = 10, 28

  • Zero Product Property

Now, notice that we have found two solutions, but the problem is only asking for one. This <em>likely </em>means that one of our solutions is extraneous. Let's take a look. Remember that the smaller positive number is equal to 14 less than the larger number. However,

s = 10 - 14 = -4,

Since s is not positive in this case, l = 10 is not a solution.


Thus, l = 28 is our only solution. In this case,

s = 28 - 14 = 14,

which means that the smaller number is 14 and the larger number is 28.

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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