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SashulF [63]
3 years ago
10

What in the world is the answers

Chemistry
1 answer:
S_A_V [24]3 years ago
5 0
There is a website for this, when I was in 7th grade I had a paper that looked exactly like this, just look up the answers until you find a website for it.
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PLEASE HELP PLEASE HELP!!
eimsori [14]

Answer:

a) positive feedback

Explanation:

positive as in increasing

5 0
4 years ago
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A reaction in which a single compound is broken down into two or more elements or new compounds
777dan777 [17]
Decomposition → ab = a +b 
4 0
3 years ago
At constant temperature, if a gas occupies 312 mL at a pressure of 1.60 atm, what pressure is necessary for this gas to occupy a
inn [45]

Answer:

P₂ = 1.0 atm

Explanation:

Boyles Law problem => P ∝ 1/V at constant temperature (T).

Empirical equation

P ∝ 1/V => P = k(1/V) => k = P·V => for comparing two different case conditions, k₁ = k₂ => P₁V₁ = P₂V₂

Given

P₁ = 1.6 atm

V₁ = 312 ml

P₂ = ?

V₂ = 500 ml

P₁V₁ = P₂V₂ => P₂ = P₁V₁/V₂ =1.6 atm x 312 ml / 500ml = 1.0 atm

5 0
3 years ago
What are the characteristics of an extrusive rock
olya-2409 [2.1K]

Extrusive Rocks. Igneous rocks which form by the crystallization of magma at the surface of the Earth are called extrusive rocks. They are characterized by fine-grained textures because their rapid cooling at or near the surface did not provide enough time for large crystals to grow.

5 0
4 years ago
A reaction mixture at equilibrium at 175 k contains ph2 = 0.958 atm, pi2 = 0.877 atm, and phi = 0.020 atm. a second reaction mix
Sophie [7]
 from ICE table
            H2(g) +  I2 (g )↔ 2HI(g)
 equ       0.958      0.877         0.02   first mix1
              0.621        0.621         0.101      sec mix2

Kp1 = P(HI)^2 / p(H2)*p(I2) for mix 1
       = 0.02^2 / 0.958*0.877
       = 4.8x10^-4
Kp2 = P(HI)^2 / P(H2)* P(I2) for mix 2
        = 0.101^2/ 0.621*0.621 
        = 0.0265
we can see that Kp1< Kp2 that means that the sec mixture is not at equilibrium. It will go left to reduce its products and increase reactant to reduce the Kp value to achieve equilibrium.

and the partial pressure of Hi when mix 2 reach equilibrium is:
4.8x10^-4 = P(Hi)^2 / (0.621*0.621)
∴ P(Hi) at equilibrium = 0.0136 atm



8 0
3 years ago
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