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katrin [286]
3 years ago
9

Some enzymes have one or more sulfhydryl (thiol) groups that are important to enzymatic activity but that can react upon standin

g in solution to form inactive disulfide bonds.
Thiol reagents, such as 1,4-dithiothreitol (DTT), are often added to the solutions of such proteins to protect them from this reaction and to reverse it when it occurs. (The reverse reaction works best at slightly alkaline pH.) Draw the product formed when DTT reacts with a protein disulfide bond to liberate the free thiol groups. Which of the following occurs in this reaction? A. The protein disulfide is oxidized.
B. The protein disulfide is reduced.
C. DTT is reduced.
D. DTT is oxidized.
Chemistry
1 answer:
Jlenok [28]3 years ago
3 0

Answer:

A. Protein disulfide is oxidized.

Explanation:

When thiol reagents are introduced with some protein solutions they react with molecules of disulfide and oxidize the protein. There occurs inter-conversion of thiol molecules into free disulfide molecules. The DTT reduces the disulfide molecules bonds of proteins and it starts to peptide.

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Halogens are good leaving groups in substitution reactions because leaving group ability is directly related to their being:____
Vlada [557]

Answer:

weak bases

Explanation:

Leaving groups accept electron pairs. A strong base donates an electron pair while a weak base accepts an electron pair.

Since good leaving groups must readily accept electrons, weak bases are very good leaving groups.

The order of usefulness of halogens as leaving groups is: I > Br > Cl > F

7 0
3 years ago
Hydrogen is a gas at a room temperature, but it is found with the alkali metals in group 1 (1A) on the periodic table. Which is
bearhunter [10]
Hydrogen is grouped with the alkali metals because they are grouped based on their properties and behavior, and like the other elements in Group 1 (1A), it only has one valence.
5 0
3 years ago
A sample of hydrated copper (II) sulfate (CuSO4•nH2O) is heated to 150°C and produces 103.74 g anhydrous copper (II) sulfate and
wariber [46]

Answer:

5

Explanation:

Firstly, we convert what we have to percentage compositions.

There are two parts in the molecule, the sulphate part and the water part.

The percentage compositions is as follows:

Sulphate- (103.74)/(103.74 + 58.55) × 100% = apprx 64%

The water part = 100 - 64 = 36%

Now, we divide the percentages by the molar masses.

For the CuSO4 molar mass is 64 + 32 + 4(16) = 160g/mol

For the H2O = 2(1) + 16 = 18g/mol

Now we divide the percentages by these masses

Sulphate = 64/160 = 0.4

Water = 36/18 = 2

The ratio is thus 0.4:2 = 1:5

Hence, there are 5 water molecules.

3 0
3 years ago
Scientist looking for new substances in plants grind up the plants with methanol. This solvent dissolves many plant compounds. H
liubo4ka [24]

Answer:

See explanation

Explanation:

Crystals can be made from methanol by recrystallizing the plant extract from methanol.

The methanol/water system is heated rapidly using a hot plate and the plant extract dissolves in the heating solution until a clear solution is obtained.

The solution is now cooled rapidly. The interior of the flask used for the re crystallization may even by scratched to assist the quick formation of crystals. Large crystals of plant compounds may be obtained using this method. This process should be carried out in a fume hood because of the toxicity of methanol.

4 0
2 years ago
Diamond has a density of 3.513 g/cm³. The mass of diamonds is often measured in "carats," where 1 carat equals 0.200
Gennadij [26K]

The volume of a 1.86-carat diamond in cubic centimeters is 0.106 cm³

Given,

The density of a diamond is  3.513 g/cm³.

We have to find out the volume of a 1.86-carat diamond in cubic centimeters.

Convert the units of the diamond from carat to grams, we have:

(1.86 carats) x (0.200 g / 1 carat) = 0.372 g

The volume of the diamond is obtained by dividing the mass by the density, therefore using the formula, we get

                            v = m / d

                            v = 0.372 g / (3.51 g/cm³) = 0.1059 cm³

                       or, v = 0.106 cm³ (approx)

Therefore, the volume of a 1.86-carat diamond is approximately 0.106 cm³.

To learn more about the volume, visit: brainly.com/question/1578538

#SPJ9

4 0
1 year ago
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