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katrin [286]
3 years ago
9

Some enzymes have one or more sulfhydryl (thiol) groups that are important to enzymatic activity but that can react upon standin

g in solution to form inactive disulfide bonds.
Thiol reagents, such as 1,4-dithiothreitol (DTT), are often added to the solutions of such proteins to protect them from this reaction and to reverse it when it occurs. (The reverse reaction works best at slightly alkaline pH.) Draw the product formed when DTT reacts with a protein disulfide bond to liberate the free thiol groups. Which of the following occurs in this reaction? A. The protein disulfide is oxidized.
B. The protein disulfide is reduced.
C. DTT is reduced.
D. DTT is oxidized.
Chemistry
1 answer:
Jlenok [28]3 years ago
3 0

Answer:

A. Protein disulfide is oxidized.

Explanation:

When thiol reagents are introduced with some protein solutions they react with molecules of disulfide and oxidize the protein. There occurs inter-conversion of thiol molecules into free disulfide molecules. The DTT reduces the disulfide molecules bonds of proteins and it starts to peptide.

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Boron (B) has two isotopes, boron-10 and boron-11. The atomic weight of boron is ?
suter [353]

Answer:

Approximately 10,5

Explanation:

The question is not really very specific, because it would need the percentages of those isotopes in the nature. As they are not shown, it should be the median of those two numbers.

atomic weight ≈ \frac{10+11}{2} = 10,5

If you check a periodic table, you'll see it's actually 10,8, but that's because of the thing I told you at first (percentages missing).

Hope I could help.

8 0
3 years ago
Which activity might help to increase the validity of this experiment?
MArishka [77]
A should be the answer because the more you test an experiment the more data you have to rely on changing the experiment would cause you to have different outcomes making the results different and unreliable so B, C, and D is not going to be the answer Hope this helps
5 0
3 years ago
Does the physical form of the material matter for mass-mole<br> and mole-mass calculations?
natulia [17]
Tin metal reacts with hydrogen fluoride to produce tin(II) fluoride and hydrogen gas according to the following balanced equation.

Sn(s)+2HF(g)→SnF2(s)+H2(g)
Sn(s)+2HF(g)→
SnF
2
(s)+
H
2
(g)

How many moles of hydrogen fluoride are required to react completely with 75.0 g of tin?

Step 1: List the known quantities and plan the problem.

Known

given: 75.0 g Sn
molar mass of Sn = 118.69 g/mol
1 mol Sn = 2 mol HF (mole ratio)
Unknown

mol HF
Use the molar mass of Sn to convert the grams of Sn to moles. Then use the mole ratio to convert from mol Sn to mol HF. This will be done in a single two-step calculation.

g Sn → mol Sn → mol HF

Step 2: Solve.

75.0 g Sn×1 mol Sn118.69 g Sn×2 mol HF1 mol Sn=1.26 mol HF
75.0 g Sn×
1
mol Sn
118.69
g Sn
×
2
mol HF
1
mol Sn
=1.26 mol HF

Step 3: Think about your result.

The mass of tin is less than one mole, but the 1:2 ratio means that more than one mole of HF is required for the reaction. The answer has three significant figures because the given mass has three significant figures.
4 0
2 years ago
Read 2 more answers
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Sergeeva-Olga [200]

Answer:

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Explanation:

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The definition of <em>equilibrium</em> is when the forward rate and the reverse rate are <em>equal</em>.

Because in the initial state there's only NO₂, there's no possibility for the reverse reaction (from N₂O₄ to NO₂). Thus the forward rate will be larger than the reverse rate.

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kipiarov [429]

Answer:

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Explanation:

i think so. not sure

6 0
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