solution:
the utmost height would be comprehensive while y'(t)=0. (on the suitable of the trajectory, the y speed is 0.)
Answer:
f = 1.5 x 10¹⁵ Hz
Explanation:
Light is an electromagnetic wave and we know that the speed of light is a constant which is
3 x 10⁸ m/s.
Knowing this; v = λ x f
λ = wavelength
f= frequency of light
v = seed of light
f = v/λ
f = 3 x 10⁸m/s / 2.0 x 10-⁷ m
f = 1.5 x 10¹⁵ Hz
<u>Answer:</u>
A measurement standard is defined as 'the exact quantity people agree to use for comparison'.
<u>Explanation:</u>
For the same type of quantity, there is a unit of measurement which is defined and adopted either conventionally or by law which is used as standard for measurement of that quantity.
This measurement standard is defined as 'the exact quantity people agree to use for comparison'.
For example, for length the standard unit of measurement is 'meter'.
Answer:
ΔU = 5.21 × 10^(10) J
Explanation:
We are given;
Mass of object; m = 1040 kg
To solve this, we will use the formula for potential energy which is;
U = -GMm/r
But we are told we want to move the object from the Earth's surface to an altitude four times the Earth's radius.
Thus;
ΔU = -GMm((1/r_f) - (1/r_i))
Where;
M is mass of earth = 5.98 × 10^(24) kg
r_f is final radius
r_i is initial radius
G is gravitational constant = 6.67 × 10^(-11) N.m²/kg²
Since, it's moving to altitude four times the Earth's radius, it means that;
r_i = R_e
r_f = R_e + 4R_e = 5R_e
Where R_e is radius of earth = 6371 × 10³ m
Thus;
ΔU = -6.67 × 10^(-11) × 5.98 × 10^(24)
× 1040((1/(5 × 6371 × 10³)) - (1/(6371 × 10³))
ΔU = 5.21 × 10^(10) J
