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Veronika [31]
2 years ago
7

A car decelerates at a rate of 3.8 m/s2 for 12 seconds. The car’s initial speed was 65 m/s. What was the car’s final speed?

Physics
1 answer:
Ostrovityanka [42]2 years ago
4 0
For an uniformly accelerated motion, the final velocity is given by:
v_f = v_i +at
where vi is the initial speed, a is the acceleration, and t the time interval.
In our problem, v_i=65 m/s, a=-3.8 m/s^2 (with negative sign, because the car is decelerating), and t=12 s. Substituting, 
v_f = 65 m/s+(-3.8 m/s^2)(12 s)=19.4 m/s

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