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inna [77]
3 years ago
10

A measurement standard is defined as ____.

Physics
2 answers:
Serggg [28]3 years ago
5 0

<u>Answer:</u>

A measurement standard is defined as 'the exact quantity people agree to use for comparison'.

<u>Explanation:</u>

For the same type of quantity, there is a unit of measurement which is defined and adopted either conventionally or by law which is used as standard for measurement of that quantity.

This measurement standard is defined as 'the exact quantity people agree to use for comparison'.

For example, for length the standard unit of measurement is 'meter'.

Blizzard [7]3 years ago
5 0

Answer:

is an object system or experiment that bears a defined relationship to a unit of measurement of a physical quality

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GREYUIT [131]

Answer:

it is 45

Explanation:

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3 years ago
a baseball player is dashing toward home plate with a speed of 200 feet per hour. When he decides to hit the dirt. he slides for
Serggg [28]

To solve this problem we will use the kinematic formula for the final velocity.


V_f_x = V_0_x + a_xt


The final speed is 0 at the moment the player stops.


The time until it stops is 1.3 s


The initial speed is 200 feet / s  Note (check the speed units in the problem statement, 200ft / s is very much and 200ft / h is very small)

Then, we clear the formula.


a_x = \frac{(Vfx-V0x)}{t}\\ a_x = \frac{(0-200)}{1.3}\\ a_x = -153.5 ft / s ^ 2

Because the player is slowing down, the acceleration goes in the opposite direction to the player's movement, and that is why it is negative.



To answer part b) we use the following formula.


Vf ^ 2 = Vo ^ 2 + 2a * (x_2 - x_1)\\\\ (x_2 - x_1)= \frac{(V_f ^ 2-V_0 ^ 2)}{2a}\\\\ (x_2 - x_1)= \frac{(0-200 ^ 2)}{- 2 * 153.5}\\\\ (x_2 - x_1)= 130.29 feet

8 0
3 years ago
The mass of a planet is 3.7 x 1024 kg. If the planet has a radius of 9.2 x 106 m what is the acceleration of gravity for a perso
nalin [4]

Explanation:

It s given that,

Mass of a planet, M=3.7\times 10^{24}\ kg

Radius of a planet, R=9.2\times 10^{6}\ m

(1) We need to find the acceleration due to gravity for a person on the surface of the planet. Its formula is given by :

g=\dfrac{GM}{R^2}

g=\dfrac{6.67\times 10^{-11}\ Nm^2/kg^2\times 3.7\times 10^{24}\ kg}{(9.2\times 10^{6}\ m)^2}

g=2.91\ m/s^2

(2) The escape velocity is given by :

v=\sqrt{\dfrac{2GM}{R}}

v=\sqrt{{\dfrac{2\times 6.67\times 10^{-11}\ Nm^2/kg^2\times 3.7\times 10^{24}\ kg}{9.2\times 10^{6}\ m}}

v = 7324.61 m/s

Hence, this is the required solution.

3 0
3 years ago
Which instrument is launched into the atmosphere to collect pressure, temperature, humidity, wind speed, and other data?
koban [17]
C. Radiosonde is the answer

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5 0
3 years ago
What are two ways to change the state of a substance?
weeeeeb [17]
Solid to liquid
Liquid to solid

By adding or removing heat energy aka thermal energy 
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3 years ago
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